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kobusy [5.1K]
3 years ago
10

two dice are rolled in succession. determine the probability that their sum is 8 or more, given that the first die is a 4 or mor

e.

Mathematics
1 answer:
viva [34]3 years ago
8 0
See the pic for answer. 

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Use the right triangular prism shown to answer the following questions.
Tju [1.3M]

Answer:

168cm is the right answer

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Solve the system by substitution.<br> -8x - y = 30<br> -2y = x
masya89 [10]

Answer:

Solution:  (-4, 2),   x= -4 and  y =2

Step-by-step explanation:

-8x - y = 30

-2y = x

Substitute for x

-8*(-2y)   - y = 30

16y  - y = 30

15y = 30

y = 30/15 = 2

Then  x = -2y = -2*(2) = -4

Solution:  (-4, 2),   x= -4 and  y =2

4 0
3 years ago
How many 7-digit phone numbers are possible, assuming that the first digit can’t be a 0 or a 1? (b) re-solve (a), except now ass
sladkih [1.3K]
A. We are going to form 7 digit numbers from the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

where the first digit cannot be 0 or 1.

so we have 8 choices for the 1. digit, and 10 choices for all the other 6 digits.

this means there are 8*10*10*10*10*10*10=8* 10^{6} possible numbers.

b.

consider the numbers which start with 911. There are 10*10*10*10=10 ^{4} such numbers, since for the 4th, 5th, 6th and 7th digits we have 10 choices.

then we remove this number, from the one we found in a:

There are in total 8* 10^{6}-10^{4}=7,990,000 numbers which don't start with 911.


Answer:

a.8*10^{6}
b.7,990,000

3 0
3 years ago
Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was
andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, p = 0.42

92% confidence level

So \alpha = 0.08, z is the value of Z that has a pvalue of 1 - \frac{0.08}{2} = 0.96, so Z = 1.75.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0
4 years ago
A gym has 563 people that want to attend workout classes. Each class will have 15 people.
Dmitrij [34]

40

why?: 563/15=37.53333333

Round up to the nearest 10

Brainliest?

3 0
3 years ago
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