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drek231 [11]
3 years ago
10

Add the two expressions 6q + 1 and q + 11

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Addition of 6q + 1 and q + 11 is 7q + 12

<em><u>Solution:</u></em>

Given that, we have to add the given two expressions

<em><u>Given expressions are:</u></em>

6q + 1 and q + 11

We have to add both the expressions

Addition of 6q + 1 and q + 11 = 6q + 1 + q + 11

Add the coefficients of same variable. Here "q" is present in two terms

Therefore, add 6q and q

Similarly, add the constants 1 and 11

<em><u>Thus finally addition is done as:</u></em>

6q + 1 + q + 11 = 7q +12

Thus addition of 6q + 1 and q + 11 is 7q + 12

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Answer:

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Step-by-step explanation:

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En una fiesta se desea elegir un grupo de 3 personas de entre 6 matrimonios, si dos miembros de la misma pareja no pueden ser el
LenaWriter [7]

Answer:

Hay 160 maneras

Step-by-step explanation:

Para calcular de cuántas maneras se puede seleccionar x elementos de un grupo de n elementos podemos usar la siguiente fórmula:

nCx=\frac{n!}{x!(n-x)!}

Si vas a elegir 3 personas de entre 6 matrimonios y dos miembros de la misma pareja no pueden ser elegidos, entonces podemos decir que se está eligiendo 3 matrimonios y en cada matrimonio se está eligiendo un representante.

Entonces, podemos calcular de cuántas maneras se puede escoger 3 matrimonios de los 6, así:

6C3=\frac{6!}{3!(6-3)!}=20

Adicionalmente, para cada uno de los 3 matrimonios hay 2 opciones para ser representantes. Esto significa que hay 2^3 maneras de escoger representantes en cada una de las 20 formas calculadas anteriormente.

Por lo tanto se puede formar el grupo de 3 personas de 160 maneras diferentes:

20*2^3=160

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3 years ago
Erik's disabled sailboat is floating stationary 3 miles east and 2 miles north of Kingston. A ferry leaves Kingston heading towa
sergij07 [2.7K]

Answer:

Step-by-step explanation:

Let's suppose that Ballard is an origin with coordinates (0;0)

Ballard is 8 miles south and 1 mile west of Edmonds ⇒ Edmonds is 1 mile east and 8 miles north of Ballard.

Thus, coordinates of Edmonds (0+1; 0+8) (1;8)

Edmonds is 6 miles due east of Kingston. So, is 6 miles due of Edmonds

Thus, Kingston coordinates (1-6;8) (-5:8)

Sailboat is 3 miles east and 2 miles north of kingston

So, coordinates of sailboat are (-5+3; 8+2) (-2;10)

a)

Ferry leaves Kingston towards Edmonds at mph and Edmonds is 6 miles due east of Kingston.

Initial ferry coordinates as calculated above are equal to Kingston coordinates (-5;8)

After 20 minutes the ferry turns to south.

This distance travelled (20min) is d=9mph*20/60h=3 miles

So, ferry travelled 3 miles toward east in 20 min

Then, coordinates became (-5+3;8+0) (-2;8)

Thus, we have a line connecting two points (-5;8) and (-2;8)

Line connecting them has an equation:

y-8 = (8-8)/(-2+5) * (x+5)

y-8=0

y=8 - This is the equation for the first 20 minutes of travel

Then, ferry turns due south (-2;8) and has a vertiacl line

The equation of verical line is x=a, so the equation will be x=2

b) The sailboat has a radar scope that will detect any object within 3 miles of the sailboat.

region looks like a circular disc with a center (-2;10)

(x+2)^2+(y-10)^2=3^2

(x+2)^2+(y-10)^2 <9 (interior of the circular disc)

(x+2)^2+(y-10)^2 >9 (exterior)

The equation of the line joining the Kingston and Edmonds is y=8

the point of intersection:

(x+2)^2+(8-10)^2=9

(x+2)^2=5

x is approximately 0.24; -4.24

(0.24;8) (-4.24;8) - intersection points

c) The ferry exits the radar during the trid due south long x=-2

The points of intersection of the circle and the line x=-2:

(-2+2)^2+(y-10)^2=9

0+(y-10)^2=0

y is 7.13

(-2;7)

d) Takes south turn at (-2;8), then ferry travels 0.8 miles up to point (-2;7) where it exists the radar zone

Speed is 9mph

The time taken to cover 1 mile = t=1/9hr=1/9 *60=6.667min

So, it exists after 6.67 minutes

e) Ferry enters at (-4.24;8) and takes turn due to south at (-2;8)

The distance travelled is = [-4.24+2]=2.24 miles

The time taken to cover these miles is = t=2.24/9 *60=14.93 min

After turning to south ferry remains in radar for 6.7 min

So, it remains in radar zone for 14.93+6.7=21.63min

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Answer: A projectile reaches its highest point when its vertical velocity component is zero.

Step-by-step explanation:

In projectile motion, objects moves in parabolic path.

Projectile motion is a type of motion in which an object moves in a bilaterally symmetrical, parabolic path. Projection motion happens when the force is applied at the start of the trajectory (where the object follows) which follows an interference which is gravity. Gravity takes over and afterwards the object accelerates downwards. The acceleration is constant so the vertical velocity (Vy) varies linearly. The maximum height of the projectile which is the highest height is reached when the vertical velocity (Vy) is equal to zero.

After the projectile reaches its maximum height which is its highest point, it begins to drop downwards.

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