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3 years ago

Add the two expressions 6q + 1 and q + 11

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

8 0

Addition of 6q + 1 and q + 11 is 7q + 12

Solution:

Given that, we have to add the given two expressions

Given expressions are:

6q + 1 and q + 11

We have to add both the expressions

Addition of 6q + 1 and q + 11 = 6q + 1 + q + 11

Add the coefficients of same variable. Here "q" is present in two terms

Therefore, add 6q and q

Similarly, add the constants 1 and 11

Thus finally addition is done as:

$6q + 1 + q + 11 = 7q +12$

Thus addition of 6q + 1 and q + 11 is 7q + 12

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3 years ago

Helpppppppp pleaseeeeee

olga nikolaevna [1]

Answer:

7a + b - 16c

Step-by-step explanation:

So we have

7a-3b+c-8c+4b-9c

When it comes to problem like these, you need to combine like terms.

There's only one 'a' number, so that one remains the same.

Next, we have -3b and 4b. (-3b+4b)= b

Finally, there's (c-8c-9c).

(-8c-9c)= -17c

Take that and add the positive 'c' to it.

(-17c+c)= -16c

Put it all together now to get:

7a + b - 16c

I hope that helped and helped you understand at least a little

6 0

3 years ago

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°

djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, $\angle ABN$ is 37°. We can see from the diagram that $\angle ABC$ would be $180-37=$ 143°.