All categories

3 years ago

Add the two expressions 6q + 1 and q + 11

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

8 0

Addition of 6q + 1 and q + 11 is 7q + 12

Solution:

Given that, we have to add the given two expressions

Given expressions are:

6q + 1 and q + 11

We have to add both the expressions

Addition of 6q + 1 and q + 11 = 6q + 1 + q + 11

Add the coefficients of same variable. Here "q" is present in two terms

Therefore, add 6q and q

Similarly, add the constants 1 and 11

Thus finally addition is done as:

$6q + 1 + q + 11 = 7q +12$

Thus addition of 6q + 1 and q + 11 is 7q + 12

You might be interested in

A local hamburger shop sold a combined total of 763 hamburgers and cheeseburgers on Saturday. There were 63 more cheeseburgers s

Airida [17]

In order to solve this we'll start by assigning variables to hamburgers and cheeseburgers, since these are what we're trying to find. Lets say x = hamburgers and y = cheeseburgers. So we know two things, we know that x+y= 763 (hamburgers plus cheeseburgers sold equals 763, and we know that y= x+63 (cheeseburgers sold equals 63 more than hamburgers sold). Now we have a system of equations. This can be solved most easily by rearranging each equation to each y, and then set them equal to each other:
x+y=763 -> y=763-x, and we already have y=x+63. Set them equal to each other:
x+63 = 763-x (add x to both sides) -> 2x+63 = 763 (subtract 63 from both sides) -> 2x = 700 (divide both sides by 2) x = 350. So we solved for x, which is hamburgers sold, which is what the question asks for, so your answer is 350 hamburgers were sold on Saturday

6 0

3 years ago

URGENT Enter the values for the highlighted variables that show how to subtract the rational expressions correctly: StartFractio

Marrrta [24]

The value of the highlighted variables ave been determined a =6, b= 2 ,c= 6 , d = 2 , e = 6 , f = 6, g =1

<h3>What is an Expression ?</h3>

An expression are mathematical statement consisting of variables , constants and mathematical operators .

The given expression is

$\rm \dfrac{2}{x^2-36} - \dfrac{1}{x^2 +6x} = \dfrac{2}{(x+6)(x-6)}-\dfrac{1}{x(x+a)}\\\\= \dfrac{bx}{x(x+6)(x-6)}-\dfrac{x-c}{(x+6)(x+6)x}\\\\= \dfrac{dx-x+e}{x(x+6)(x-6)}\\\\= \dfrac{x+f}{x(x+6)(x-6)}\\\\= \dfrac{g}{x(x-6)}$

a = 6

b= 2

c= 6

d = 2

e = 6

f = 6

g =1

Therefore the value of the highlighted variables ave been determined.

To know more about Expression

brainly.com/question/14083225

#SPJ1

3 0

2 years ago

Which of the following are the zeros of the function y= 3(x-a)(x+b) in terms of a and b?

frosja888 [35]

The correct answer is option 2.

3 = 0

x - a = 0

x = a

x + b = 0

x = -b

We do not multiply any of these values by 3 because in a way, 3 is acting as another "zero" of the equation. Though, as shown above, it does not equal 0, it still does not apply to any of the other equations solved above.

Hope this helps!! :)

7 0

3 years ago

PLEASE ANSWER Which characteristic is shared by both prokaryotes and eukaryotes?

Norma-Jean [14]

Answer:

the 3rd one,

Step-by-step explanation:

Because it is the 3rd one

7 0

3 years ago

Read 2 more answers

What’s the surface area

DerKrebs [107]

Answer:

Step-by-step explanation:

7 0

3 years ago