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zzz [600]
3 years ago
7

Madeline solved this problem: A basketball player made 10 shots and scored 26 points. She made only two-point and three-point sh

ots. How many of each type of shot did she make? Complete the statement about Madeline’s solution. Math item stem image CLEARCHECK In Madeline's solution, 6 is the number of -point shots and 4 is the number of -point shots.
Mathematics
1 answer:
ankoles [38]3 years ago
3 0

Answer:

six is 3 pointers 4 is the 2 pointers

Step-by-step explanation:

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Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217
Soloha48 [4]

Answer:

f(216) \approx 6.0093

Step-by-step explanation:

Given

\sqrt[3]{217}

Required

Solve

Linear approximated as:

f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)

Take:

x = 216; \triangle x= 1

So:

f(x) = \sqrt[3]{x}

Substitute 216 for x

f(x) = \sqrt[3]{216}

f(x) = 6

So, we have:

f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)

f(215 + 1) \approx 6  +1 \cdot f'(x)

f(216) \approx 6  +1 \cdot f'(x)

To calculate f'(x);

We have:

f(x) = \sqrt[3]{x}

Rewrite as:

f(x) = x^\frac{1}{3}

Differentiate

f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}

Split

f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}

f'(x) = \frac{x^\frac{1}{3}}{3x}

Substitute 216 for x

f'(216) = \frac{216^\frac{1}{3}}{3*216}

f'(216) = \frac{6}{648}

f'(216) = \frac{3}{324}

So:

f(216) \approx 6  +1 \cdot f'(x)

f(216) \approx 6  +1 \cdot \frac{3}{324}

f(216) \approx 6  + \frac{3}{324}

f(216) \approx 6  + 0.0093

f(216) \approx 6.0093

6 0
3 years ago
The base of a 13 foot ladder is 5 feet away from the wall. How far up the wall does the ladder reach? A)8 feet B)10 feet C)12 fe
Lisa [10]

You are solving for the height. Use the formula:

c² - b² = a²      in which c = hypotenuse

(13)² - (5)² = a²

Simplify

169 - 25 = a²

144 = a²

Isolate the a. Root both sides

√144 = √a²

a = √144

a = √(12 x 12)

a = 12

C) 12 feet is your answer

~

3 0
3 years ago
Read 2 more answers
What is the least number of solution a quadratic system can have
Setler79 [48]
The least number of quadratic system can have is Two real solutions or no real solutions. 
8 0
3 years ago
Which expression is equivalent to sec2x − 1?
hichkok12 [17]
<span><span>tan^2</span>(x) is the answer.</span>
6 0
3 years ago
36-4c-3c=22 I don't understand how to solve for c
LiRa [457]
Subtract 36 from both sides making it: -4c-3c=-14
Now subtract -4c and 3c making it: -7c=-14
Now divide by -7 on both sides making it: c=2
There you go
3 0
3 years ago
Read 2 more answers
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