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zzz [600]
3 years ago
7

Madeline solved this problem: A basketball player made 10 shots and scored 26 points. She made only two-point and three-point sh

ots. How many of each type of shot did she make? Complete the statement about Madeline’s solution. Math item stem image CLEARCHECK In Madeline's solution, 6 is the number of -point shots and 4 is the number of -point shots.
Mathematics
1 answer:
ankoles [38]3 years ago
3 0

Answer:

six is 3 pointers 4 is the 2 pointers

Step-by-step explanation:

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Help me with my algebra final exam please.​
kvasek [131]

Answer:

its b

Step-by-step explanation:

8 0
3 years ago
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The petronas towers in Kuala Lumpur, Malaysia, are 452 meters tall. A woman who is 1.75 meters tall stands 120 meters from the b
bazaltina [42]

Answer:

75.1^{\circ}

Step-by-step explanation:

In this problem, we have:

H = 452 m is the height of the Petronas tower

h = 1.75 m is the height of the woman

d = 120 m is the distance between the woman and the base of the tower

First of all, we notice that we want to find the angle of elevation between the woman's hat the top of the tower; this means that we have consider the difference between the height of the tower and the height of the woman, so

H' = H-h = 452-1.75=450.25 m

Now we notice that d and H' are the two sides of a right triangle, in which the angle of elevation is \theta. Therefore, we can write the following relationship:

tan \theta = \frac{H'}{d}

since

H' represents the side of the triangle opposite to \theta

d represents the side of the triangle adjacent to \theta

Solving the equation for \theta, we find the angle of elevation:

\theta = tan^{-1}(\frac{H'}{d})=tan^{-1}(\frac{450.25}{120})=75.1^{\circ}

3 0
3 years ago
Ujalakhan help! (x+2)(y-1) Simplify.
Gekata [30.6K]

Answer:

We can use the distributive property.

(x + 2)(y - 1)

= x(y) - x(1) + 2(y) - 2(1)

= xy - x + 2y - 2

4 0
3 years ago
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For questions 13-15, Let Z1=2(cos(pi/5)+i Sin(pi/5)) And Z2=8(cos(7pi/6)+i Sin(7pi/6)). Calculate The Following Keeping Your Ans
weqwewe [10]

Answer:

Step-by-step explanation:

Given the following complex values Z₁=2(cos(π/5)+i Sin(πi/5)) And Z₂=8(cos(7π/6)+i Sin(7π/6)). We are to calculate the following complex numbers;

a) Z₁Z₂ = 2(cos(π/5)+i Sin(πi/5)) * 8(cos(7π/6)+i Sin(7π/6))

Z₁Z₂ = 18 {(cos(π/5)+i Sin(π/5))*(cos(7π/6)+i Sin(7π/6)) }

Z₁Z₂ = 18{cos(π/5)cos(7π/6) + icos(π/5)sin(7π/6)+i Sin(π/5)cos(7π/6)+i²Sin(π/5)Sin(7π/6)) }

since i² = -1

Z₁Z₂ = 18{cos(π/5)cos(7π/6) + icos(π/5)sin(7π/6)+i Sin(π/5)cos(7π/6)-Sin(π/5)Sin(7π/6)) }

Z₁Z₂ = 18{cos(π/5)cos(7π/6) -Sin(π/5)Sin(7π/6) + i(cos(π/5)sin(7π/6)+ Sin(π/5)cos(7π/6)) }

From trigonometry identity, cos(A+B) = cosAcosB - sinAsinB and  sin(A+B) = sinAcosB + cosAsinB

The equation becomes

= 18{cos(π/5+7π/6) + isin(π/5+7π/6)) }

= 18{cos((6π+35π)/30) + isin(6π+35π)/30)) }

= 18{cos((41π)/30) + isin(41π)/30)) }

b) z2 value has already been given in polar form and it is equivalent to 8(cos(7pi/6)+i Sin(7pi/6))

c) for z1/z2 = 2(cos(pi/5)+i Sin(pi/5))/8(cos(7pi/6)+i Sin(7pi/6))

let A = pi/5 and B = 7pi/6

z1/z2 = 2(cos(A)+i Sin(A))/8(cos(B)+i Sin(B))

On rationalizing we will have;

= 2(cos(A)+i Sin(A))/8(cos(B)+i Sin(B)) * 8(cos(B)-i Sin(B))/8(cos(B)-i Sin(B))

= 16{cosAcosB-icosAsinB+isinAcosB-sinAsinB}/64{cos²B+sin²B}

= 16{cosAcosB-sinAsinB-i(cosAsinB-sinAcosB)}/64{cos²B+sin²B}

From trigonometry identity; cos²B+sin²B = 1

= 16{cos(A+ B)-i(sin(A+B)}/64

=  16{cos(pi/5+ 7pi/6)-i(sin(pi/5+7pi/6)}/64

= 16{ (cos 41π/30)-isin(41π/30)}/64

Z1/Z2 = (cos 41π/30)-isin(41π/30)/4

8 0
3 years ago
Solve number (4) please
AVprozaik [17]

Answer:

Step-by-step explanation:

x=25

5 0
3 years ago
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