Answer:

Step-by-step explanation:
Given
![\sqrt[3]{217}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B217%7D)
Required
Solve
Linear approximated as:

Take:

So:
![f(x) = \sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
Substitute 216 for x
![f(x) = \sqrt[3]{216}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7B216%7D)

So, we have:



To calculate f'(x);
We have:
![f(x) = \sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
Rewrite as:

Differentiate

Split


Substitute 216 for x



So:





You are solving for the height. Use the formula:
c² - b² = a² in which c = hypotenuse
(13)² - (5)² = a²
Simplify
169 - 25 = a²
144 = a²
Isolate the a. Root both sides
√144 = √a²
a = √144
a = √(12 x 12)
a = 12
C) 12 feet is your answer
~
The least number of quadratic system can have is Two real solutions or no real solutions.
<span><span>tan^2</span>(x) is the answer.</span>
Subtract 36 from both sides making it: -4c-3c=-14
Now subtract -4c and 3c making it: -7c=-14
Now divide by -7 on both sides making it: c=2
There you go