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3 years ago

Find the area of a Semicircle whose radius is 3.5 cm (take pi as 22/7

Mathematics

2 answers:

Vera_Pavlovna [14]3 years ago

4 0

Answer:

TSA=115.5cm²

Step-by-step explanation:

T.S.A=3πr²

Given r=3.5cm

eq.

3×22/7×3.5×3.5

=3×22×0.5×3.5

=115.5cm²

Roman55 [17]3 years ago

4 0

Answer:

$19.25cm^{2} \\$

Step-by-step explanation:

<u>Formula</u>

<u />

<u>Solve</u>

<u /> $\frac{(\frac{22}{7} )(3.5cm)^{2}}{2}= \frac{(\frac{22}{7} )(3.5cm)(3.5cm)}{2}=\frac{((\frac{22}{7} )(3.5cm))(3.5cm)}{2}=\frac{(\frac{77}{7}cm)(3.5cm) }{2}$ =

$\frac{(11cm)(3.5cm)}{2}=\frac{38.5cm^{2}}{2}=19.25cm^{2}$

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4 0

3 years ago

Work out the circumference of this circle.

svetoff [14.1K]

Answer:

circumference=2\pi r

25.12cm

Step-by-step explanation:

hope this helps

4 0

3 years ago

Please correct both problems...and if I'm doing something PLEASE HELP,me

Vanyuwa [196]

Answer:

1. g(f(-2)) = -19

2. f(f(-1)) = -1

Step-by-step explanation:

1. g(f(-2)) where f(x) = 5x + 2 and g(x) = 2x-3

you're on the right track! g(f(x)) means that g's x is equal to the function f, in which you would plug in the answer for f (or equation in some cases) and that would be the x term of g. g(f(x)) or (g°f) can be said as "g composed of f"

what i would do first to make it a bit more simpler is plug in -2 in f(x) and then plug in that answer into g(f(x))

f(-2) = 5(-2) + 2 = -10 + 2 = -8

f(-2) = -8

in your steps, you put g(-2) = -8, when it is f(-2) = -8,

what you would do after that is plug in -8 into g(f(x))

g(f(-8)) = g(-8) <-- plug in -8 for x in g(x)

g(-8) = 2(-8) - 3 <-- distribute 2 into -8

-16 - 3 = -19

so g(f(-2)) = -19

2. find f(f(-1)) when f(x) = 8 - x

first you want to solve f(-1)

f(-1) = 8 - (-1) = 9

so f(-1) = 9

again, what you did in this composition is solved for the first function (the inside f), but never plugged in the result into the second function

now we want to plug in the answer 9 into f(x)

f(9) = 8 - (9) = -1

so f(9) = -1

this leaves us with the answer: f(f(-1)) = -1

7 0

3 years ago

the area of a rectangular invitation card is 3/10 square foot. Given that the length of the card is 4/5 foot, find its perimeter

Troyanec [42]

Length = 4/5 ft
area = 3/10 ft.
Width = 3/10 ÷ 4/5 ft
= 3/10*5/4 ft
= 3/8 ft

Perimeter = 2(L+W)
= 2(4/5+3/8) ft
= 2(32+15)/40 ft
= 47/20 ft
= 2.35 ft

5 0

3 years ago

I need help with this<br> 2(5x+4)=

N76 [4]

4/5

2(5x+4)=

distribute the 2

10x+8=

subtract 8 from both sides

10x=8

divide 10 from both sides

x=8/10

simplify by 2

x= 4/5

7 0

3 years ago

Read 2 more answers

Find the area of a Semicircle whose radius is 3.5 cm (take pi as 22/7​

Find the area of a Semicircle whose radius is 3.5 cm (take pi as 22/7