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4 years ago

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Three students work independently on a homework problem. The probability that the first student solves the problem is 0.95. The

probability that the second student solves the problem is 0.85. The probability that the third student solves the problem is 0.80. What is the probability that all are able to solve the problem

1 answer:

ludmilkaskok [199]4 years ago

5 0

Answer:

64.60% probability that all are able to solve the problem

Step-by-step explanation:

We have these following probabilities:

A 95% probability that the first student solves the problem.

An 85% probability that the second student solves the problem.

An 80% probability that the third student solves the problem.

What is the probability that all are able to solve the problem

The probabilities are independent, so we can just multiply them

0.95*0.85*0.8 = 0.646

64.60% probability that all are able to solve the problem

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7Bx%2B1%7D%20%2B%5Cfrac%7B3%28x-1%29%7D%7Bx%7D%20%3D5" id="TexFormula1" title=

Luden [163]

Answer:

$x=-3$

Step-by-step explanation:

<u>Given equation</u>:

$\dfrac{2x}{x+1}+\dfrac{3(x+1)}{x}=5$

Make the <u>denominators</u> the same:

$\implies \dfrac{2x}{x+1} \cdot\dfrac{x}{x}+\dfrac{3(x+1)}{x} \cdot \dfrac{x+1}{x+1}=5$

$\implies \dfrac{2x^2}{x(x+1)}+\dfrac{3(x+1)^2}{x(x+1)} =5$

<u>Combine</u> the fractions:

$\implies \dfrac{2x^2+3(x+1)^2}{x(x+1)} =5$

<u>Multiply</u> both sides by x(x+1):

$\implies 2x^2+3(x+1)^2 =5x(x+1)$

<u>Expand</u> the brackets:

$\implies 2x^2+3(x^2+2x+1) =5x^2+5x$

$\implies 2x^2+3x^2+6x+3 =5x^2+5x$

<u>Combine</u> like terms:

$\implies 5x^2+6x+3=5x^2+5x$

<u>Subtract</u> 5x² from both sides:

$\implies 6x+3=5x$

<u>Subtract</u> 5x from both sides:

$\implies x+3=0$

<u>Subtract</u> 3 from both sides:

$\implies x=-3$

Learn more about algebraic fractions here:

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2 years ago

Think of an example in your life where a number could be described as data, information, and knowledge.

Nat2105 [25]

Answer:

how many event you have been too in the last month (well non during this time but as an example)

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3 years ago

Read 2 more answers

I need help pls help me in geometry homework

djverab [1.8K]

You can use photo math but the first one is b

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3 years ago

If f(x) = 4x + 3 and g(x) = 3x, evaluate for X = -1/2

miskamm [114]

Answer:

$f(-\frac{1}{2}) = 1$

$g(-\frac{1}{2} ) = -\frac{3}{2}$

Step-by-step explanation:

Given the function $f(x) = 4x + 3$ and the function $g(x) = 3x$ , to evaluate for $x=-\frac{1}{2}$ , you need to substitute it into each function.

Then, for the function f(x), when $x=-\frac{1}{2}$ , you get:

$f(-\frac{1}{2}) = 4(-\frac{1}{2}) + 3$

$f(-\frac{1}{2}) = 4(-\frac{1}{2}) + 3$

$f(-\frac{1}{2}) = -\frac{4}{2}+ 3$

$f(-\frac{1}{2}) = -2 + 3$

$f(-\frac{1}{2}) = 1$

For the function g(x), when $x=-\frac{1}{2}$ , you get:

$g(-\frac{1}{2} ) = 3(-\frac{1}{2})$

$g(-\frac{1}{2} ) = -\frac{3}{2}$

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3 years ago

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In our industry on average a firm paid out record year end bonuses of $125,500 per employee for 2008. We would like to take a sa

Rina8888 [55]

Answer:

Step-by-step explanation:

Given that in our industry on average a firm paid out record year end bonuses of $125,500 per employee for 2008. We would like to take a sample of employees at our firm to see whether the mean year end bonus is different from the reported mean of $125,500 for the population.

1. Sample Mean = 118000

2. Population Mean = 125500

3. Population Standard Deviation = 30000

4. Sample size = 40

5. Alpha Error = 5%

6. Confidence Coefficient = 95%

7. Calculate Test Statistic = Mean difference /s td error = -1.581

8. Rejection Region Critical Value = If Z statistic is below -1.96 or above 1.96

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3 years ago