Question

The following observed values of x and y are thought to satisfy a linear equation. Write the linear equation.

Answer 1

Slope=(-2-6)/(6--6)=-8/12=-2/3
use point slope formula
y+2=-2/3(x-6)
y=-2/3x + 2. in slope intercept

I) cuts x axis at (-4/3,0)
I) cuts y axis at (0,2)

Answer 2

Answer:

Step-by-step explanation:

Given are two points on a straight line.

(since x and y are thought to satisfy a linear equation. )

The two points are (x,y) = (6,-2) (-6,6)

Use the two point formula for finding equation

Two point formula is

$\frac{y-y_1}{y_2-y_1}= \frac{x-x_1}{x_2-x_1}$

Substitue the values to get

$\frac{x-(-6)}{6-(-6)} =\frac{y-6}{-2-6} \\x+6 =\frac{12}{-8}(y-6) \\-2x-12=3y-18\\2x+3y=6$

is the equation

This can also be written in intercept form as

$\frac{x}{3} +\frac{y}{2} =1$

Hence x intercept = 3 and y intercept = 2