Answer:
<em>good luck, i hope this helps :)</em>
A quarter occupies a space of 0.6 cm3 and contains 2.50 times as much material as a dime. The area of a dime’s face is 2.52 cm2.
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Given:
h(t) = 25 - a·t²
h(0.5) = 21
Find:
t such that h(t) = 0
Solution:
h(0.5) = 25 - a·0.5² = 21
25 - 21 = a/4
4·4 = a = 16
Then
h(t) = 25 - 16t²
We want h(t) = 0, so
0 = 25 - 16t²
16t² = 25
t² = 25/16 = (5/4)²
t = 5/4 = 1.25
It takes 1.25 seconds for the entire 25 ft drop.
h(t) = 25 - a·t²
h(0.5) = 21
Find:
t such that h(t) = 0
Solution:
h(0.5) = 25 - a·0.5² = 21
25 - 21 = a/4
4·4 = a = 16
Then
h(t) = 25 - 16t²
We want h(t) = 0, so
0 = 25 - 16t²
16t² = 25
t² = 25/16 = (5/4)²
t = 5/4 = 1.25
It takes 1.25 seconds for the entire 25 ft drop.