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Andrej [43]
3 years ago
13

An artist used a scale factor of 1 in=8 ft to create a model of a building. if the actual building has a height of 64 feet, how

many feet are they apart?
Mathematics
1 answer:
nalin [4]3 years ago
8 0

Answer:

<em>Okay, so what I think you mean to ask what the scale factor between the model and actual building</em> is, so i crunched the numbers. if 1 in equaled 8 feet and the actual thing was 64 ft, then we can just say that 64 divided by 12 is 5.3, so the model could be

5.3 ft. is the size of the model

BUT

you said how many feet are they apart so in inches its 705, in ft its 58.75

Step-by-step explanation:

a foot is 12 in.

64/12 is 5.3

64 ft is 768 inches, and 5.3 is 63.

768-63 = 705.

there are 705 inches in difference, in feet its 58.75

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4 years ago
Y=-x^2+20x-64 what is the max height
Inessa [10]

Answer:

36

Step-by-step explanation:

The maximum height is the y-coordinate of the vertex

given a quadratic in standard form : ax² + bx + c : a ≠ 0

then the x-coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = - x² + 20x - 64 is in standard form

with a = - 1, b = 20 and c = - 64, hence

x_{vertex} = - \frac{20}{-2} = 10

substitute x = 10 into the equation for y

y = - (10)² + 20(10) - 64 = 36 ← max height


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3 years ago
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9 * 4 = 36

180 + 36 = 216

So 9 * 24 = 216
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