Answer:
afafasfafd shfgjsuhd shdfhsdfghn isndfhusudhfuh nsu
Step-by-step explanation:
dsfshdfh jishudfnhuj hudsnfhjnshjdnf nsjndfjnsdhjnf jhsdnjfhnsdhjnf usndfhsndhjfnshjn jshbndfjhsednfjhn ddhn hshhdfhdsh hhjis ndfjnsd ndfsjhnfh jinse hdfj sihdfhisnhnsd nsdfnshuidfhisdfhjsihjdfnihjsdhfsdj hdhshi dhsdhfsdh dhujishisdfuyhsdhujnghjigihjsdghnsdih huiedsnfghjixhui dyun9y un9sguyhsdyhugnsdghjigsngnih hunxcvhjio nidjnxcgyhui
Answer:
6.31 mi
Step-by-step explanation:
The diagram below explains the solution better.
From the diagram,
C = starting point of the race.
A = end of the first part of the race.
B = end of the race.
Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.
Cosine rule states that:
![a^2 = b^2 + c^2 - 2bc[cos(A)]](https://tex.z-dn.net/?f=a%5E2%20%3D%20b%5E2%20%2B%20c%5E2%20-%202bc%5Bcos%28A%29%5D)
where A = angle A = <A
Given that
b = 5.2 miles
c = 2.0 miles
<A = 115° (from the diagram)
Hence,
![a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi](https://tex.z-dn.net/?f=a%5E2%20%3D%205.2%5E2%20%2B%202.0%5E2%20-%202%2A5.2%2A2.0%5Bcos%28115%29%5D%5C%5C%5C%5Ca%5E2%20%3D%2027.04%20%2B%204%20-%2020.8%5Bcos%28115%29%5D%5C%5C%5C%5Ca%5E2%20%3D%2031.04%20%2B%208.79%5C%5C%5C%5Ca%5E2%20%3D%2039.83%5C%5C%5C%5Ca%20%3D%20%5Csqrt%7B39.83%7D%5C%5C%20%5C%5Ca%20%3D%206.31%20mi)
The straight-line distance between the starting point and the end of the race is 6.31 mi
Answer:
10 and 40
Step-by-step explanation:
Find the prime factorization of 10
10 = 2 × 5
Find the prime factorization of 40
40 = 2 × 2 × 2 × 5
Multiply each factor the greater number of times it occurs to find the LCM:
LCM = 2 × 2 × 2 × 5
LCM=40
Answer: 177.4999849 , or 56.5pi
Step-by-step explanation:
You simply divide the diameter by 2 to get the radius (28.25) and then plug into the circumference equation, 2*pi*r = Circumfrence.
Answer:
x = 44
Step-by-step explanation:
3x - 5 is complementary to y° so their sum is 180°
The angle with measure 127° is also complementary with y°
127 + y = 180
y = 53°
53 + 3x - 5 = 180
3x + 48 = 180
3x = 132
x = 44
