solution
this is what I did. total number of ways without any restriction =900. we have to subtract the case when at least one child doesn't get any fruit. let that be C1∪C2∪C3 and we use the principle of mutual inclusion and exclusion to find that. C1∪C2∪C3=C1+C2+C3−(all two intersections)+3 intersections (no one gets a fruit case) =3⋅60−3+1=178 so case where each child gets at least one fruit =900−178=722.
Is this right, someone saying answer =49
Answer:
1: -2
2: -3
(-2,-3)
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
5x2=10
<span>The minimum wage in 2003 was $5. Let denote this minimum wage with: W_min_2003.
In 1996 the minimum wage was 15 the W_min_2003 ,so we can write:
W_min_1996=15*W_min_2003=15*5 USD= 75 USD.
The minimum wage in 1996 was 75 USD.</span>
Answer:
=102
Step-by-step explanation:
17=1/6 of the price
x=1/1 of the price
x=1*17*6=102