Answer:
9.4 m
Explanation:
We can use a moving frame of reference with the same speed as the car. From this frame of reference the car doesn't move. The origin is at the back of the car, the positive X axis points back and the positive Y axis points up.
If the ballon is launched at 9.7 m/s at 39 degrees of elevation.
Vx0 = 9.7 * cos(39) = 7.5 m/s
Vy0 = 9.7 * sin(39) = 6.1 m/s
If we ignore air drag, the baloon will be subject only to the acceleration of gravity. We can use the equation of position under constant acceleration.
Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2
Y0 = 0
a = -9.81 m/s^2
It will fall when Y(t) = 0
0 = 6.1 * t - 4.9 * t^2
0 = t * (6.1 - 4.9 * t)
t1 = 0 (this is when the balloon was launched)
0 = 6.1 - 4.9 * t2
4.9 * t2 = 6.1
t2 = 6.1 / 4.9 = 1.25 s
The distance from the car will be the horizonta distance it travelled in that time
X(t) = X0 + Vx0 * t
X(1.25) = 7.5 * 1.25 = 9.4 m
It could never actually happen like this, but the question is
looking for you to 'conserve' the momentum.
Momentum of a moving object is (mass) x (velocity).
Like velocity, momentum has a direction.
Momentum is one of those things that's 'conserved'.
That means that momentum can't appear out of nowhere, and
it doesn't disappear. The total after the collision is the same as
the total was before the collision.
Momentum of the skinny player:
(70 kg) x (3 m/s north) = 210 kg-m/s north.
Momentum of the heavy player:
(80 kg) x (1.5 m/s south) = 120 kg-m/s south .
Total momentum before the collision is
(210 kg-m/s north) + (120 kg-m/s south)
= 90 kg-m/s north .
It has to be the same after the collision.
(mass) x (velocity) = 90 kg-m/s north.
The mass after the collision is 150 kg, because they get
tangled up and stuck together, and they move together.
(150 kg) x (velocity) = 90 kg-m/s north .
Divide each side
by 150 kg : velocity = (90 kg-m/s north) / (150 kg)
= (90/150) (kg-m/s / kg north)
= 0.6 m/s north .
Answer:
the weight of the large stone is greater than a small one
Explanation:
because the large stone has greater mass then the small stone.therefore it is difficult to lift the large stone on the surface of the earth but easy to lift the small one
