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Delicious77 [7]
4 years ago
5

On the periodic table, which group of elements is not possible to form an ionic bond with?

Physics
2 answers:
Igoryamba4 years ago
7 0

Answer: 18 group.

The group 18 elements of periodic table never forms a ionic bond. Only this group is the exception where all the elements present in the group does not form any ionic bond. There are other elements also that do not form ionic bonds but not complete group. The noble atoms have complete outer shell so they can neither lose or gain any electron which form the group 18.

Nookie1986 [14]4 years ago
3 0
The Noble Gases because all of their shells are full; thus, they have no charge. If they have no charge, then we cannot form ionic bonds with them.
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3 years ago
*please refer to photo* An electric field of magnitude 5.25 ✕ 10^5N/C points due south at a certain location. Find the magnitude
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Approximately 3.86\; {\rm N} (given that the magnitude of this charge is -7.35\; {\rm \mu C}.)

Explanation:

If a charge of magnitude q is placed in an electric field of magnitude E, the magnitude of the electrostatic force on that charge would be F = E\, q.

The magnitude of this charge is q = 7.35\; {\rm \mu C}. Apply the unit conversion 1\; {\rm \mu C} = 10^{-6}\; {\rm C}:

\begin{aligned} q &= 7.35\; {\mu C} \times \frac{10^{-6}\; {\rm C}}{1\; {\mu C}} = 7.35\times 10^{-6}\; {\rm C}\end{aligned}.

An electric field of magnitude E = 5.25\times 10^{5}\; {\rm N \cdot C^{-1}} would exert on this charge a force with a magnitude of:

\begin{aligned}F &= E\, q \\ &= 5.25 \times 10^{5}\; {\rm N \cdot C^{-1}} \times (-7.35\times 10^{-6}\; {\rm C}) \\ &\approx 3.86\; {\rm N}\end{aligned}.

Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.

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