You have a reservoir held at a constant temperature of –30°C. You add 400 J of heat to the reservoir. If you have another reserv
oir at 0°C, how much heat must you add to it so that both reservoirs have the same increase in entropy?
1 answer:
Answer:
449.38 J
Explanation:
ΔS = ΔQ/T
Where ΔS = entropy change
Q = quantity of heat
T = temperature
First reservoir :
T = –30°C = - 30 + 273 = 243K
Q = 400 J
Second reservoir :
T = 0°C = 273K
Q =?
To have same increase in entropy for both reservoirs :
Q/T of first reservoir = Q/T of second reservoir
400/243 = Q/273
243 * Q = 400 * 273
Q = (400 * 273) / 243
Q = 109,200 / 243
Q = 449.38271
Q = 449.38 J
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Hope this helps.
Answer:
D
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Please let me know if this helped! Please rate it the brainlist if possible!
I think it’s B because we aren’t looking for Vf
