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Pie
4 years ago
13

You have a reservoir held at a constant temperature of –30°C. You add 400 J of heat to the reservoir. If you have another reserv

oir at 0°C, how much heat must you add to it so that both reservoirs have the same increase in entropy?
Physics
1 answer:
marysya [2.9K]4 years ago
6 0

Answer:

449.38 J

Explanation:

ΔS = ΔQ/T

Where ΔS = entropy change

Q = quantity of heat

T = temperature

First reservoir :

T = –30°C = - 30 + 273 = 243K

Q = 400 J

Second reservoir :

T = 0°C = 273K

Q =?

To have same increase in entropy for both reservoirs :

Q/T of first reservoir = Q/T of second reservoir

400/243 = Q/273

243 * Q = 400 * 273

Q = (400 * 273) / 243

Q = 109,200 / 243

Q = 449.38271

Q = 449.38 J

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a block has a volume of 0.09m3 and a density of 4,000kg/m3. what's the force of gravity acting on the block in water
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       Density = (mass) / (volume)

                                4,000 kg/m³ = (mass) / (0.09 m³)

Multiply each side
by  0.09 m³ :           (4,000 kg/m³) x (0.09 m³) = mass

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                           = (360 kg) x (9.8 m/s²)

                           = (360 x 9.8)  kg-m/s²

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That's the force of gravity on this block, and it doesn't matter 
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