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loris [4]
3 years ago
5

A plant dying after being exposed to poison represents a physical change. True False

Physics
2 answers:
nlexa [21]3 years ago
8 0

Answer:

chemical change as death is irreversible

nasty-shy [4]3 years ago
5 0

Answer:

It does not represent a physical change

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Which of the following is NOT common of elite Shang burials?
Zigmanuir [339]

Answer:

Large above ground mausoleums were not common in the elite Shang burials.

Explanation:

Large, above the ground mausoleums were not common so the answer is option B.

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2 years ago
In which space, outdoors or in your classroom, would it be easier to hear a musician? Explain
bixtya [17]

Answer:

It is easier to hear a musician in the classroom than outdoors

Explanation:

It is easier to hear a musician in the classroom due to the improved acoustics provided by the walls of the classroom whereby along with the direct sound of the musician, which is the lead source of the sounds, there is an increased number of indirect sound reaching the ear in the classroom than outdoors and due to precedence effect, all the sound appear to come from the musician

In music played outside, along side the direct sound from the musician, the indirect sound that reach the ear is echoed from maybe by only the ground while the majority of the sound from the music wanders away with the wind and in other directions as well as being absorbed such that speakers will be required to improve the sound of the music outdoors.

7 0
3 years ago
Suppose you were asked to demonstrate electromagnetic induction. Which of the following situations will result in an electric cu
steposvetlana [31]
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5 0
3 years ago
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The second law of thermodynamics says that whenever energy is converted from one form to another in a physical or chemical chang
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3 0
3 years ago
A block of mass m is pushed up against a spring, compressing it a distance x, and the block is then released. The spring project
Gwar [14]

Answer:

x' = 10 x

Explanation:

By energy conservation we know that spring energy is converted into kinetic energy of the block

so we will have

\frac{1}{2}kx^2 = \frac{1}{2}mv^2

so we will have

v = \sqrt{\frac{k}{m}}(x)

now we will have same thing for another mass 4m which moves out with speed 5v

so we have

5v = \sqrt{\frac{k}{4m}}(x')

now from above two equations we have

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so we have

x' = 10 x

3 0
2 years ago
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