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Effectus [21]
3 years ago
12

Please help 10 points for grabs

Mathematics
1 answer:
Scrat [10]3 years ago
3 0
Where’s the question
You might be interested in
How many solutions does a triangle with side lengths a = 4, A = 112º and b =<br>9 have?​
Ainat [17]

Answer:

This case has NO solutions.

Step-by-step explanation:

Notice that you are in a case of an obtuse triangle (one of its angles is larger than 90 degrees), the side opposite to the obtuse triangle is shorter than the side adjacent to the angle, so no actual triangle can be formed.

This can be found by simply trying to apply the Law of Sines to solve for the value of angle "B" opposite to side "b":

\frac{sin(A)}{a} =\frac{sin(B)}{b}\\sin(B)=\frac{b\,sin(A)}{a}\\sin(B)=\frac{9\,sin(112^o)}{4}\\\\sin(B)=2.086

As shown above, we get an impossible mathematical condition (also call an absurd), since the sine of an angle cannot give a value larger than 1 (one).

Therefore, there is no angle we can find to build a triangle with the given data.

7 0
3 years ago
Can I get help with this question?
worty [1.4K]
The answer is 157 degrees because the line segment is 180 and if <AFB is 23, you take 23 away from 180 and you should get 157. To check, add 157 to 23 or take away 157 from 180.
8 0
4 years ago
On the same graph draw line 2y-x=10 and y=3x​
Luba_88 [7]

Answer:

Step-by-step explanation:

7 0
3 years ago
A car travels 9 miles in 7 minutes. How fast is it going in miles per hour? How fast is it going in meters per second?
Tems11 [23]

Answer:

he's going 77mph and then 2069 meters per hour.

8 0
2 years ago
Help with algebra pls help
EastWind [94]

9514 1404 393

Answer:

  a. 1.48 seconds

Step-by-step explanation:

You want to find the larger value of t such that h(t) = 10.

  -16t^2 +25t +8 = 10

  16t^2 -25t +2 = 0 . . . . subtract the left side to get standard form

Using the quadratic formula, we find the values of t to be ...

  t = (-(-25) ± √((-25)^2 -4(16)(2)))/(2(16)) = (25±√497)/32

  t ≈ 0.08 or 1.48

The ball goes in the hoop about 1.48 seconds after it is thrown.

__

<em>Additional comment</em>

The quadratic formula tells us the solution to ...

  ax² +bx +c = 0

is given by ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, we have a=16, b=-25, c=2. Of course, our variable is t, not x, but the relation is the same.

8 0
3 years ago
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