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3 years ago

14

Justin bought a 20 pound pumpkin for $9.80. Kyle bought a 5 pound pumpkin for $2.60. Who got a better deal on their pumpkin? Be

specific with your numbers.

1 answer:

sveta [45]3 years ago

6 0

20-9.80=?

5.-2.60=?

Find out. Solve them.

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4x+x+6=11x-6x+6 what is the value for x

sveticcg [70]

Answer:

use papamath it will give u the anwers

Step-by-step explanation:

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3 years ago

Find the slope of the line through the points (6,16) and (−6,4)

MakcuM [25]

$m = \frac{y2-y1}{x2-x1}$

$m = \frac{4-16}{-6-6} \\m = \frac{-12}{-12} \\\\m = 1$

Therefore, the slope of the line is 1. In case if you want to know the equation.

$y=mx+b\\y=x+b\\4=-6+b\\4+6=b\\10=b\\$

Therefore, the equation is y=x+10 by substituting the (-6,4) or we can substitute (6,16) too.

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It's the same, you can use any orders given.

Overall, the slope is 1 and the equation is y=x+10

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3 years ago

Find the value of a in the parallelogram.

S_A_V [24]

6a-4 = 3a+54
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2 years ago

Student attendance at football games

Paladinen [302]

Collin's sampling method will better represent the entire population.

<h3>Missing part of the question</h3>

Determine which sampling method will better represent the entire population.

<h3>How to determine the better method?</h3>

From the question, we understand the Collin selected random names from the school directory.

While Karl surveyed only the students sitting close to him.

Karl's method is biased because students sitting far from him do not have a chance of being surveyed.

Hence, Collin's sampling method will better represent the entire population.

Read more about sampling method at:

brainly.com/question/16587013

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2 years ago

A police department reports that the probabilities that 0, 1, 2, and 3 burglaries will be reported in a given day are 0.53, 0.40

SpyIntel [72]

The mean of the probability distribution is given by the expected value given by

$E(x)=\sum xp(x) \\ \\ =0(0.53)+1(0.40)+2(0.05)+3(0.02) \\ \\ =0.40+0.10+0.06=0.56$

The variance of the probability distribution is given by

$Var(x)=(x-\bar{x})^2p(x) \\ \\ =(0-0.56)^2(0.53)+(1-0.56)^2(0.40)+(2-0.56)^2(0.05)\\+(3-0.56)^2(0.02) \\ \\ =(-0.56)^2(0.53)+0.44^2(0.40)+1.44^2(0.05)+2.44^2(0.02) \\ \\ =0.3136(0.53)+0.1936(0.40)+2.0736(0.05)+5.9536(0.02) \\ \\ =0.166208+0.07744+0.10368+0.119072=0.4664$

The standard deviation is given by

$\sigma(x)=\sqrt{Var(x)} \\ \\ =\sqrt{0.4664}=0.683$

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2 years ago