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olga55 [171]
3 years ago
7

Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, the

n m=m equals negative StartFraction 1 Over 6 EndFraction.. What is the value of b? −6 −5 5 6
Mathematics
2 answers:
NeX [460]3 years ago
5 0

Answer:

m = -1/6.

b = 5.

Step-by-step explanation:

Slope m =  (3 - 6) / (12 - -6)

=  -3 / 18

= -1/6.

y = -1/6 x + b

when x = 12 y = 3 so

3 = -1/6 * 12 + b

b =  3 + 2 = 5.

Aloiza [94]3 years ago
3 0

Answer: 5

Step-by-step explanation:

We can find our intercept b from the equation of the straight line:

y - y₁ = m (x-x₁ )

point A(-6, 6)

x₁ = -6 and y₁ =6

m= -1/6 (as stated in the question)

Inputing this values in our equation, we have;

y - 6 = -1/6 ( x - -6)

y - 6 = -1/6(x+6)

y - 6 = -1/6x -1

y = -1/6x - 1 + 6

y= -1/6x + 5

comparing y= mx+b with the equation above; b=5

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Solve #2 with an explanation please
KatRina [158]
The fence is 210 ft long.
There is a post every 3.5 ft.
If you divide 210 ft by 3.5 ft, you get the number of spaces between posts.
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Here's another way of thinking of why you end up with 60 posts.
For each 3.5 ft of fencing, you place a post at the end of the fencing.
Since there are 60 3.5-ft-long pieces of fencing, there will be 60 posts, one at the end of each piece of fencing. The first thing that is done is to put the initial post before any fencing is put up. The first post plus 60 more posts add up to 61 posts.

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5 0
3 years ago
Which vector matrix represents the reflection of the vector <-1,5> across the line x = y
Arturiano [62]

Answer:

V = \left[\begin{array}{ccc}5&-1\end{array}\right]

Step-by-step explanation:

We want to reflect this 2x1 vector on the line y = x.

To make this reflection we must use the following matrix:

R=\left[\begin{array}{cc}0&1\\1&0\\\end{array}\right]

Where R is known as the reflection matrix on the line x = y

Now perform the product of the vector <-1,5> x R.

\left[\begin{array}{ccc}-1\\5\end{array}\right]x\left[\begin{array}{ccc}0&1\\1&0\end{array}\right]\\\\\\\left[\begin{array}{ccc}-1(0) +5(1)&-1(1)+5(0)\end{array}\right]\\\\\\\left[\begin{array}{ccc}5&-1\end{array}\right]

The vector matrix that represents the reflection of the vector <-1,5> across the line x = y is:

V = \left[\begin{array}{ccc}5&-1\end{array}\right]

6 0
3 years ago
I need help with that, if you can, plz. I ty it I think is a not sure
STALIN [3.7K]

Answer:

-5≤x <1

Step-by-step explanation:

sqrt( x+5) / sqrt(1-x)

The numerator must be greater than zero since it is a square root

sqrt(x+5) ≥0

Square each side

x+5≥0

x≥-5

The denominator must be greater than zero (the denominator cannot be zero)

sqrt(1-x)> 0

Square each side

1-x > 0

1>x

Putting these together

-5≤x <1

5 0
3 years ago
What is this? Please answer with an explanation
Dima020 [189]

Answer:

Slope = -2

Step-by-step explanation:

Since, slope = \frac{\text{Rise}}{\text{Run}}

Rise = -(y-intercept)

Run = (x-intercept)

From the graph attached,

y - intercept = -(4) = -4

x - intercept = 2

Therefore, slope the line given in the graph attached will be,

Slope = \frac{-4}{2} = -2

Slope = -2

4 0
3 years ago
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