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katovenus [111]
3 years ago
8

the hight, the feet, of a javelin t seconds afther it is moldeled by the function (t) =4t^2 + 24t + 6. Afther how many seconds d

oes the javelin reah its maximum height of 42 feet?
Mathematics
1 answer:
ruslelena [56]3 years ago
8 0
The max height will be reached after 3 seconds.

You have a typo in your equation. For this type of quadratic equation, it always starts out with a negative coefficient of the t squared term.

To find the x-coordinate of the vertex, we just need to use the expression: -b/2a.

Then, we have:

-24 / (2(-4))

-24 / -8

3
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Given that (-1,-2) is on the graph of f(x) find the corresponding point for the function f(x)+4.
Scilla [17]
Answer: (-1,2)

To get this answer, you add 4 to the y coordinate of the given point. Every point on f(x) is shifted up four units when we go from f(x) to f(x)+4. The x coordinate stays the same. 
5 0
3 years ago
Solve the quadratic equation by completing the square.<br> x^2+2x-2=0
astraxan [27]

The solution to the quadratic equation by completing the square is x = -1 + √3, x = -1 - √3

<h3>What is a quadratic equation?</h3>

Any equation of the form \rm ax^2+bx+c=0  where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}

We have a quadratic equation:

x² + 2x - 2 = 0

x² + 2x + 1 - 1 - 2 = 0

(x + 1)² - 3 = 0

(x + 1)² = 3

x + 1 = ± √3

x = -1 ± √3

Thus, the solution to the quadratic equation by completing the square is x = -1 + √3, x = -1 - √3

Learn more about quadratic equations here:

brainly.com/question/2263981


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5 0
2 years ago
What is 2 thirds plus 3 sevenths
Zepler [3.9K]
23 over 21 is the right answer

23
----
21
6 0
3 years ago
Read 2 more answers
Using exactly four 4's and any operations[+,-,x,/,()] write an expression to equal each of the following:
IrinaK [193]
3 = 4 - 4^0 * 4/4

4 =  4^0 + 4^0 + 4^0 + 4^0

5 = 4^2 / (4^0 * 4)  + 4^0

6  = 4^2 / 4  + 4^0 + 4^0


4 0
3 years ago
In parallelogram QRST QS RT Is QRST a rectangle ?
fomenos

Answer:

The correct option is A.

Step-by-step explanation:

It is given that the QRST is a parallelogram and the diagonals QS and RT are congruent.

According to the property of parallelogram if the length of diagonals are same, then the parallelogram is rectangle. We can also prove it.

Let QRST be an parallelogram and QS=RT.

In triangles QRT and RQS.

RT=QS         (Diagonals)

QR=QR         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QRT and triangle RQS are congruent.

By CPCT,

\angle R=\angle Q

Since the sum of two consecutive angles of a parallelogram is 180 degree.

\angle R+\angle Q=180

2\angle R=180

\angle R=90

Therefore the measure of angle R and angle Q are 90 degree.

Similarly in triangle QST and RTS,

RT=QS         (Diagonals)

ST=ST         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QST and RTS are congruent.

By CPCT,

\angle S=\angle T

Since the sum of two consecutive angles of a parallelogram is 180 degree.

Therefore the measure of angle S and angle T are 90 degree.

Since the measure of all interior angles of QRST are 90 degree, therefore the parallelogram QRST  is a rectangle.

6 0
4 years ago
Read 2 more answers
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