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Lelechka [254]
3 years ago
12

whats shape has a larger area: a rectangle that is 7 inches by 3/4 inches? or a square with a side length of 2 1/2 inches

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0
The square because it has an area of 6.25
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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
Can someone help me with 3,4 and 5? For 3 and 4 it's asking "what is the volume of each solid? Round to the nearest tenth if nec
Marianna [84]

Answer:

the answer 3,b

4,f

5,c

7 0
3 years ago
Jana earns $25 per week for mowing the lawn and deposits the money into her savings account. The amount of money in Jana’s accou
Tems11 [23]

Answer: y-int = That means the amount of money in Jana's account before she began mowing lawns.

Step-by-step explanation:

The y-intercept represents the initial money that Jana has in his account. Step-by-step explanation: Given the equation of line is . Also, Jana earns $ per week. And is the number of weeks she has been working. If we plug week in the equation . It will give us the y-intercept. That means the amount of money in Jana's account before she began mowing lawns. The y-intercept represents the initial money that Jana has in his account.  

5 0
3 years ago
A peach orchard owner wants to maximize the amount of peaches produced by her orchard.
qaws [65]

Answer:

  a) Y(x) = {900, x≤30; 900-40(x-30), x>30}

  b) T(x) = {900x, x≤30; 2100x-40x², x>30}

  c) dT/dx = {900, x≤30; 2100-80x, x>30}

Step-by-step explanation:

a) The problem statement gives the function for x ≤ 30, and gives an example of evaluating the function for x = 35. So, replacing 35 in the example with x gives the function definition for x > 30.

\displaystyle Y(x)=\left\{\begin{array}{lcl}900&\text{for}&x\le 30\\900-40(x-30)&\text{for}&x>30\end{array}\right.

__

b) The yield per acre is the product of the number of trees and the yield per tree:

  T(x) = x·Y(x)

\displaystyle T(x)=\left \{\begin{array}{lcl}900x&\text{for}&x\le 30\\2100x-40x^2& \text{for}&x>30\end{array}\right.

__

c) The derivative is ...

\displaystyle\frac{dT}{dx}=\left \{\begin{array}{lcl}900&\text{for}&x\le 30\\2100-80x& \text{for}&x>30\end{array}\right.

_____

The attached graph shows the yield per acre (purple, overlaid by red for x<30), the total yield (black), and the derivative of the total yield (red). You will note the discontinuity in the derivative at x=30, where adding one more tree per acre suddenly makes the rate of change of yield be negative.

6 0
3 years ago
Passing through (5, -4) and parallel to the line whose equation is y=-2x+3;<br> point-slope form
Marina CMI [18]
The answer is y=-2x+6

8 0
3 years ago
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