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gulaghasi [49]
3 years ago
14

Show workings please

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0

Answer: x = 21°

Step-by-step explanation:

37 + 4x + (3x - 4) = 180°   Original Equation

37 + 4x + 3x - 4 = 180°   Commutative Property of Addition

7x + 33 = 180°   Combine like terms

7x = 148°  Subtract 33 from both sides

x = 21°   Divide both sides by 7

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ale4655 [162]

Answer:

answer for given question is 108045

5 0
2 years ago
Write each of the following expressions without using absolute value: PLEASE HELP I WILL MAKE BRAINLIEST TO WHOEVER GETS BOTH OF
nignag [31]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
9d-4d-2d+8=-3d help pls
goblinko [34]

Answer:

-8/3 = d OR -2 2/3

Step-by-step explanation:

9d-4d-2d+8=-3d               Well first combine all like terms

3d+8=-3d                Now isolate the variable by subtracting 4d from both sides

3d(-3d) + 8= -3d (-3d)

8= -3d                             Divide both sides by -3

-8/3 = d OR -2 2/3

6 0
3 years ago
Solve the system of linear equations by substitution.<br> 2x-y=3<br> x+5y=14
Arturiano [62]

Answer:

x= 29/11 or y= 25/11

Step-by-step explanation:

2x - y= 3 ...........equation 1

x + 5y= 14 ............equation 2

Make x the subject of the formula in equation 2

x= 14 - 5y ..............equation 3

Substitute x=14 - 5y in equation 1

2(14- 5y) - y=3

28 - 10y - y=3

Collect like terms

-10y - y=3 - 28

-11y= -25

divide both sides by coefficient of y

-11y/-11 = -25/-11

y= 25/11

Substitute y= 25/11 in equation 3

x=14 - 5(25/11)

x= 14 - 125/11

x= 29/11

6 0
3 years ago
Factor 5v^2 - 23v - 10​
AfilCa [17]

Answer:

(5v + 2)(v - 5)

Step-by-step explanation:

Hello!

The expression is written in the form of ax^2 + bx + c

Let's factor by grouping:

ac  = -50

The sum of the factors of -50 should add up to -23.

-25 and 2 work for this.

Expand and factor:

  • 5v^2 - 23v - 10
  • 5v^2 - 25v + 2v - 10
  • 5v(v - 5) +2(v -5 )
  • (5v + 2)(v - 5)

The factored expression is (5v + 2)(v - 5)

7 0
2 years ago
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