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3 years ago

PLEASE HELP WILL GIVE 40 POINTS AND BRAINLIEST

Mathematics

1 answer:

timama [110]3 years ago

5 0

Answer:

1. (-4,0) (0,2)

2. (6,0) (0,3)

3. (-4.5,0) (0,-3)

Btw theirs desmos.com that has a graph calculator

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What is the answer to this along with steps to doing it?

pashok25 [27]

1/2*(2*8)=3*(-12)
1/2*16=3*(-12)
1/2*16= -36
8= -36
The equality is false because the left hand and right hand side are different

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2 years ago

Which equations represent exponential growth? Which equations represent are exponential decay?

Lera25 [3.4K]

Answer:

When the base is less than 1 it's Decay

When the base is greater than 1 it's Growth

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2 years ago

Find the function value, if possible. (If an answer is undefined, enter UNDEFINED.)

ddd [48]

Answer:

f(x + 2) = 3x + 2

Step-by-step explanation:

Simply replace wherever you find x in the function f(x) with (x + 2), like so:

f(x + 2) = 3(x + 2) - 4

f(x + 2) = 3x + 6 - 4

f(x + 2) = 3x + 2

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3 years ago

Evaluate the expression: v ? w Given the vectors: r = <8, 1, -6>; v = <6, 7, -3>; w = <-7, 5, 2> . If the answ

Snezhnost [94]

Answer:

-13

Step-by-step explanation:

Given are two vectors v and w.

v=(6,7,-3) and

w=(-7,5,2)

We are to find the dot product of v.w

We have

Dot product is obtained by multiplying corresponding pairs and adding them

Here we have

v.w=6(-7)+7(5)-3(2)

=-13

7 0

3 years ago

Please help

ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

$x^2+4y^2=100\\4y-x^2=-20$

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

$4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100$

Now we can solve for y:

$4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5$

So plugging in y = 4 into an equation and solving for x, we have:

$x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6$

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

5 0

3 years ago