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Sholpan [36]
2 years ago
7

Solve the inequality: -8(8x – 16) < 64(2 – 2).

Mathematics
1 answer:
Jet001 [13]2 years ago
8 0

Answer:

The answer is D. all real numbers

Step-by-step explanation:

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Find the perimeter of a tringle that had sides 1 1/8 1 3/8 1 5/8
pychu [463]

Answer:A


Step-by-step explanation: Add the 1s first, you get 3, then add 3/8 and 5/8 and you Get 1. 3 +1 is 4 plus the remainder of 1/8


7 0
3 years ago
Use synthetic division to determine whether the number k is an upper or lower bound (as specified for the real zeros of the func
mote1985 [20]

Solution:

The given Polynomial is :

f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5})

By Rational Root theorem the  of Zeroes of the Polynopmial are:

\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4

But , f(\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4)\neq 0

So, no root of this polynomial is real.

Therefore, All the four roots of Polynomial are imaginary.

So, we can't say whether the number k=2, is an upper or lower bound of the polynomial f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5}).

8 0
3 years ago
Read 2 more answers
Divide -3x^3-2x^2-x-2 by x-2
Rasek [7]

Let's do this by Briot-Ruffini


First: Find the monomial root


x - 2 = 0

x = 2


Second: Allign this root with all the other coeficients from equation

Equation = -3x³ - 2x² - x - 2

Coeficients = -3, -2, -1, -2

2 | -3 -2 -1 -2


Copy the first coeficient


2 | -3 -2 -1 -2

-3


Multiply him by the root and sum with the next coeficient


2.(-3) = -6

-6 + (-2) = -8


2 | -3 -2 -1 -2

-3 -8


Do the same


2.(-8) = -16

-16 + (-1) = -17


2 | -3 -2 -1 -2

-3 -8 -17


The same,


2.(-17) = -34

-34 + (-2) = -36


2 | -3 -2 -1 -2

-3 -8 -17 -36


Now you just need to put the "x" after all these numbers with one exponent less, see


2 | -3x³ - 2x² - 1x - 2

-3x² - 8x - 17 -36


You may be asking what exponent -36 should be, and I say:


None or the monomial. He's like the rest of this division, so you can say:


(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:

(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)


Just divide the rest by the monomial.

5 0
3 years ago
Face north. do a 1/4 turn clockwise which way will i be facing
Alla [95]

Answer:

You will be facing in a 90 degree angle.

Step-by-step explanation:

Did you mean like on a compass?

5 0
3 years ago
Read 2 more answers
Find of the areas of the squares PQRSto that of ABCD where PQ=9cm and AB=5cm​
Ket [755]

Answer: Area of square PQRS is 81cm^2 and of ABCD is 25cm^2

You know its a square. Which means all the sides are equal and same length. If you dont know what's a square then here is the definition:

Square is a plane figure with four equal sides and four right (90°) angles.

So now we know both of are squares, in case of the first square, PQRS, one side length is already given which is PQ=9cm. Now one side is 9cm which means all the sides are 9cm's (PQ=9cm, QR=9cm, RS=9cm,SP=9cm). So to find area just multiply them:

9cm * 9cm = 81cm^2

Now you found the area of the first square. So for the second square, ABCD, one side length is 5 cm so all the rest three sides are also 5 cm. Again, multiply them in order to find the area:

5cm * 5cm = 25cm^2

So square PQRS is 81cm^2 to that of square ABCD is 25cm^2

CAUTIONS: IT IS NOT THAT HARD YA KNOW

By the way, hope it helps! ^^

7 0
2 years ago
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