ANYTHING FROM NEGATIVE INFINTIY AND POSTIVE INFINITY
Answer:
Step-by-step explanation:
Not exactly sure what your question is - I am assuming that it is something like:
Show/prove that for any integer x, x^2 - x is even.
Suppose that x is an even integer. The product of an even integer and any other integer is always even (x = 2n, so x * y = 2 n * y which is even. Therefore x^2 is even. An even minus an even is even. (The definition of an even number is that it is divisible by 2 or has a factor of 2. So the difference of even numbers could be written as 2*( the difference of the two numbers divided by 2); therefore the difference is even)
Suppose that x is an odd integer. The product of 2 odd numbers is odd - each odd number can be written as the sum of an even number and 1; multiplying the even parts with each other and 1 will produce even; multiplying the 1's will produce 1, so the product can be written as the sum of an even number and 1 - which is an odd number. The difference between two odd numbers is even - the difference between the even parts is even (argument above), the difference between 1 and 1 is zero, so the result of the difference is even.
x^2 is therefore even if x is even and odd if x is odd; The difference x^2 - x is even by the arguments above.
Times the corner and bases
$55.00 is the interest due
Answer:(a) x - 0.7 = 1.5
Step-by-step explanation:
Determine whether each of the following is a solution of x − 0.7 = 1.5: (a) x = 1 (b) x = −0.8 (c) x = 2. Step 1. Substitute the number for the variable in the equation.
Step 2. Simplify the expressions on both sides of the equation.
Step 3. Determine whether the resulting equation is true.
If so, the number is a solution.
If not, the number is not a solution.
