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ohaa [14]
4 years ago
15

Printing machine A and printing machine B print the same newspaper printout, but machine B prints at half the rate of machine A.

If each machine produces 200 newspaper printouts, and both operate at different times for a total of 4 hours, what is the rate of each printing machine
Mathematics
1 answer:
klemol [59]4 years ago
6 0

Answer:

The answer is below

Step-by-step explanation:

Let us assume the rate of printing in machine A is x per hour and the rate for machine B is y. Given that machine B prints at half the rate of machine A, therefore:

y = (1/2)x                       (1)

Also, both machine produces 200 newspaper printouts, and both operate at different times for a total of 4 hours. Therefore:

200/x + 200/y = 4       (2)

Put y = (1/2)x in equation:

\frac{200}{x}+\frac{200}{(\frac{1}{2} )x}=4\\ \\ \frac{200}{x}+\frac{400}{x}=4\\\\Multiply\ through\ by\ x:\\\\200+400=4x\\\\4x=600\\\\x=150

Put x = 150 in equation y:

y=(1/2)150 = 75

Therefore the rate of machine A is 150 newspapers per hour while that of machine B is 75 newspapers per hour

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Hello from MrBillDoesMath!

Answer:

x = 10


Discussion:

A plane triangle contains 180 degrees. Adding the angles in the triangle shown in  #8 gives

(4x + 7) + (3x + 13) + 90 = 180


Note the "right angle" shown in the triangle has been replaced by its 90 degree equivalent in the above equation.

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