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3 years ago

18.96 x 2.03 correct to 2 significant figures equals what?

Mathematics

1 answer:

Andreas93 [3]3 years ago

6 0

9514 1404 393

Answer:

Step-by-step explanation:

The product of the given numbers is 38.4888. Rounding this to two significant digits gets you 38.

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An injection-molded part is likely to be obtained from any one of 8 cavities on a mold. Round your answers to three decimal plac

konstantin123 [22]

Answer:

(b) The probability is 0.375

Step-by-step explanation:

The probability is calculated as a division between the number of options that satisfy a condition and the total number of options.

For part (b), we have 8 cavities or options for obtain the part but we want to obtain the part from cavity 1, 2 or 3, so we have 3 options. Therefore, the probability is:

$\frac{3}{8} = 0.375$

For part (c), We have 8 cavities or options for obtain the part and we want to obtain the part from any cavity except cavity 3 or 4, so we have 6 options. These options are cavity 1, cavity 2, cavity 5, cavity 6, cavity 7 and cavity 8. Then, the probability is:

$\frac{6}{8} = 0.750$

3 0

3 years ago

Each of the 12 cards shown has a number and a color or pattern. Each card is equally likely to be drawn. Find each probability.

Sever21 [200]

Answer:

A) P(stars) = 1/3

B) P(odd)= 4/7

C)P(solid grays or stars or striped)= 1

D)P(1,4 or 7)= 3/7

E)P(not striped)= 2/3

Step-by-step explanation:

Given:

sample set contains 1-7 solid gray, 1-7 stars and 1-7 striped cards

Let solid gray be x

stars be y

striped be z

then sample set be

1x,2x,3x,4x,5x,6x,7x,

1y,2y,3y,4y,5y,6y,7y,

1z,2z,3z,4z,5z,6z,7z

total number of cards in sample set =21

Now

a)Finding probability of stars

Number of star cards in above sample set = 7

P(stars)= 7/21

P(y)=1/3

b)Finding probability of odd

Number of odd cards in above sample set = 12

P(odd)= 12/21

=4/7

c)Finding probability of solid grays or stars or striped

P(solid grays or stars or striped) = P(x or y or z)

=P(x U y U z)

As the events are mutually exclusive

P(x U y U z)= P(x)+P(y)+P(z)

now P(x)= 1/3

P(y)=1/3

P(z)=1/3

P(x U y U z) = 1/3 + 1/3 + 1/3

= 3/3

d)Finding probability of 1,4 or 7

Number of 1,4 or 7 cards in above sample set = 9

P(1,4 or 7) = P(1 U 4 U 7)

As the events are mutually exclusive

P(1,4 or 7) = P(1) + P(4) + P(7)

P(1)= 3/21

=1/7

P(4)= 3/21

=1/7

P(7)= 3/21

=1/7

P(1,4 or 7)= 1/7 + 1/7 + 1/7

=3/7

e)Finding probability of not striped

Number of not striped cards in above sample set = 14

P(not striped)= 14/21

= 2/3 !

6 0

3 years ago

At noon, train A leaves Bridgton heading

Snezhnost [94]

I'd say maybe by 5:30 b would

4 0

3 years ago

10 to the 5th power plus 10 to the -1 power

Serggg [28]

1000000+1/10. There are no rules for when you add the powers.

8 0

4 years ago

Riley was determined to be on the basketball team. He started practicing for 40 minutes on the first day, and then increased his

Alexeev081 [22]

Answer:

With Riley's pattern, he will practice 2,000 total minutes in 25 days.

Step-by-step explanation:

Since Riley increased his practice time by 20, 20 times 40 is 80 minutes. And since he is repeating this in total of 25 days, 80 times 25 is 2,000.

Hope this helped you in some way. If not, then let me know.

4 0

3 years ago

Read 2 more answers