Question

40 g of calcium reacts with 71 g of chlorine to produce _____ g of calcium chloride

Answer 1

The answer is 111g of calcium chloride

Answer 2

Answer: 111 g

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles of calcium}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{40g}{40g/mol}=1mole$

$\text{Number of moles of chlorine}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{71g}{71g/mol}=1mole$

$Ca+Cl_2\rightarrow CaCl_2$

1 moles of calcium react with 1 mole of chlorine to give 1 mole of calcium chloride.

Mass of calcium chloride =$moles\times {\text {molar mass}}=1mol\times 111g/mol=111g$

Thus 111 g of calcium chloride is produced.