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3 years ago

40 g of calcium reacts with 71 g of chlorine to produce _____ g of calcium chloride

Chemistry

2 answers:

grin007 [14]3 years ago

8 0

The answer is 111g of calcium chloride

Andreas93 [3]3 years ago

5 0

Answer: 111 g

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles of calcium}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{40g}{40g/mol}=1mole$

$\text{Number of moles of chlorine}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{71g}{71g/mol}=1mole$

$Ca+Cl_2\rightarrow CaCl_2$

1 moles of calcium react with 1 mole of chlorine to give 1 mole of calcium chloride.

Mass of calcium chloride = $moles\times {\text {molar mass}}=1mol\times 111g/mol=111g$

Thus 111 g of calcium chloride is produced.

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3 years ago

Determine whether you can swim in 1.00 x 10^27 molecules of water.

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Answer:

We can not swim in 1.00 × 10²⁷ molecules of water

Explanation:

The given number of molecules of water = 1.00 × 10²⁷ molecules

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$N_A$ ≈ 6.0221409 × 10²³ molecules/mol

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Therefore, we have;

The number of moles of water present in 1.00 × 10²⁷ molecules, n = (The number of molecules of water) ÷ $N_A$

∴ n = (1.00 × 10²⁷ molecules)/(6.0221409 × 10²³ molecules/mol) = 1,660.53902857 moles

The mass of one mole of water = The molar mass of water = 18.01528 g/mol

The mass, 'm', of water in 1,660.53902857 moles of water is given as follows;

Mass = (The number of moles of the substance) × (The molar mass of the substance)

∴ The mass of the water in the given quantity of water, m = 1,660.53902857 moles × 18.01528 g/mol ≈ 29.9150756 kg.

The density pf water, ρ = 997 kg/m³

Volume = Mass/Density

∴ The volume of the water present in the given quantity of water, v = 29.9150756 kg/(997 kg/m³) ≈ 30.0050909 liters

The volume of the water present in 1.00 × 10²⁷ molecules of water ≈ 30.0 liters

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Therefore, we can not swim in the given quantity of 1.00 × 10²⁷ molecules = 30.0 liters water

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