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irga5000 [103]
3 years ago
7

Two samples of carbon tetrachloride were decomposed into their constituent elements. One sample produced 38.9 g of carbon and 45

1 g of chlorine, and the other sample produced 14.8 g of carbon and 135 g of chlorine. Are these results consistent with the law of definite proportions? Show why or why not.
Chemistry
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

No.

Explanation:

The results mentioned are <u>not consistent </u>with the law of definite proportions.

Law of definite proportions states that a chemical compound contains exactly the same elements in the same proportion by weight independent of its source and method of it's preparation.

In the given question, the first sample contains 38.9 g of carbon and 451 g of chlorine that means the sample has 8% of carbon and 92% of chlorine.

On the other hand, second sample contains 14.8 g of carbon and 135 g of chlorine which means that this sample has 10% of carbon and 90% of chlorine.

Since the constituent elements in both the samples are not in fixed and constant proportions (by mass), the law of definite proportions fails here.

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A sample of carbon monoxide occupies 4.63 L at 296.0 K and 737 torr. Find its volume at −29°C and 432 torr.
Ganezh [65]

Answer:

The new volume at -29°C and 432 torr is 6.51 L

Explanation:

Step 1: Data given

Initial volume of CO = 4.63 L

Initial temperature = 296.0 K

Initial pressure = 737 torr = 737/760 = 0.9697 atm

Step 2: Calculate the new volume

(P1*V1)/T1  = (P2*V2)/T2

V2 = (P1V1*T2) / (T1*P2)

⇒ with P1 = the initial pressure = 0.9697 atm

⇒ with V1 = the initial volume = 4.63 L

⇒ with T1 = The initial temperature = 296.0 K

⇒ with T2 = the new temperature = -29.0 + 273 = 244 K

⇒ with P2 = the new pressure = 432/760 = 0.5684 atm

V2 = (P1V1/T1) * (T2/P2)

V2 = 6.51 L

The new volume at -29°C and 432 torr is 6.51 L

5 0
4 years ago
Compute the molar enthalpy of combustion of glucose (C6 H12O6 ): C6 H12O6 (s) + 6 O2 (g) → 6 CO2 (g) + 6 H2 O (g) Given that com
lana66690 [7]

Answer:

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

Explanation:

Step 1: Data given

Mass of glucose = 0.305 grams

Combustion of 0.305 grams causes a raise of 6.30 °C

Calorimeter has a heat capacity of 755 J/°C

Molar mass of glucose = 180.2 g/mol

Step 2: The balanced equation

C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (g)

Step 3:

ΔH = (m * C * ΔT + c(calorimeter) * ΔT)

with m = mass of the solutin = 0.305 grams

with C = heat capacity of water = 4.184 J/g°C

with ΔT = the change in temperature = 6.30 °C

with c(calorimeter) = 755 J/°C

ΔH = 0.305 * 4.184 *6.30 + 755 * 6.30  = 4764.5 J ( negative because it's exothermic)

Step 4: Calculate moles of glucose

Moles glucose = mass glucose / Molar mass glucose

Moles glucose = 0.305 grams / 180.2 g/mol

Moles glucose = 0.00169 moles

Step 5: Calculate molar enthalpy

Molar enthalpy = -4764.5 J / 0.00169 moles

Molar enthalpy = - 2819254.2 J/moles = -2819.3 kJ/moles

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

5 0
3 years ago
Where is the friction that allows the skater to complete the move that is occurring in this image? a girl ice skating © Wildcow
adelina 88 [10]

Answer:

C. The point of contact between the skates and the ice

Explanation:

That is the only point of friction with the ice that provides the ability to complete the move.

4 0
4 years ago
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7nadin3 [17]
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3 0
3 years ago
An 8 oz serving of whole milk has 8.0 g of fat, 8.0 g of protein, and 13 g of carbohydrates. Approximately how many kilocalories
dsp73
<h3>Answer:</h3>

156 calories

<h3>Explanation:</h3>
  • Carbohydrates, proteins and fats are food substances used by living organisms to generate energy required for the day to day activities.
  • They supply energy which differs per gram for each food substance.
  • That is;

1 g of carbohydrate = 4 calories

1 g of fat = 9 calories

1 g of protein = 4 calories

Therefore, whole milk serving containing 8.0 g of fat, 8.0 g of protein and 13 g of carbohydrates will contain the following number of calories;

8.0 g of fat = 8 g × 9 cal/g = 72 calories

8.0 g of protein = 8 g × 4 cal/g = 32 calories

13 g of carbohydrates = 13 g × 4 cal/g = 52 calories

Total amount of energy = 156 calories

Therefore, an 8 oz serving of whole milk contains 156 calories

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3 years ago
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