Given:
rate = k [A]2
concentration is
0.10 moles/liter
rate is 2.7 × 10-5 M*s-1
Required:
Value of k
Solution:
rate = k [A]2
2.7 × 10-5 M*s-1
= k (0.10 moles/liter)^2
k = 2.7 x 10^-3
liter per mole per second
.5336
using avogadro’s law
Answer:
450g of coke (C)
Explanation:
Step 1:
The balanced equation for the reaction is given below:
3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)
Step 2:
Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.
This is illustrated below:
Molar Mass of C = 12g/mol
Mass of C from the balanced equation = 3 x 12 = 36g
Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Step 3:
Determination of the mass of C required to produce 950g of CS2. This is illustrated below:
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Therefore, Xg of C will react to produce 950g of CS2 i.e
Xg of C = (36 x 950)/76
Xg of C = 450g
From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.
Sodium Phosphide has a formula of Na3P . In order to bond ionically the charges must be equal and opposite. It will take one -3 phosphide ion to balance three +1 sodium ions forming a magnesium phosphide molecule of Na3P
