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erastova [34]
4 years ago
9

Pb(NO3)2 + K2CO3 --> PbCO3 + KNO3 A. 5 B. 2 C. 4

Chemistry
1 answer:
emmasim [6.3K]4 years ago
4 0

Answer:

Pb(NO3)2 + K2CO3 ----> PbCO3 + 2KNO3

The answer is B. 2

Hope this helps!

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The rate law for a hypothetical reaction is rate = k [A]2. When the concentration is 0.10 moles/liter, the rate is 2.7 × 10-5 M*
Oksanka [162]

Given:

rate = k [A]2

concentration is 0.10 moles/liter

rate is 2.7 × 10-5 M*s-1

Required:

Value of k

Solution:

rate = k [A]2

2.7 × 10-5 M*s-1 = k (0.10 moles/liter)^2

k = 2.7 x 10^-3 liter per mole per second

5 0
4 years ago
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using avogadro’s law
6 0
3 years ago
Carbon disulfide, CS2, can be made from coke, C(s), and sulfur dioxide, SO2(g). C(s) + SO2(g) à CS2(s) + CO2(g) If the actual yi
Virty [35]

Answer:

450g of coke (C)

Explanation:

Step 1:

The balanced equation for the reaction is given below:

3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)

Step 2:

Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.

This is illustrated below:

Molar Mass of C = 12g/mol

Mass of C from the balanced equation = 3 x 12 = 36g

Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Step 3:

Determination of the mass of C required to produce 950g of CS2. This is illustrated below:

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Therefore, Xg of C will react to produce 950g of CS2 i.e

Xg of C = (36 x 950)/76

Xg of C = 450g

From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.

6 0
3 years ago
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PIT_PIT [208]

Answer:

I hope it helps

Explanation:

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4 years ago
How many sodium atoms are in the formula for sodium phosphide
ludmilkaskok [199]

Sodium Phosphide has a formula of Na3P . In order to bond ionically the charges must be equal and opposite. It will take one -3 phosphide ion to balance three +1 sodium ions forming a magnesium phosphide molecule of Na3P

6 0
3 years ago
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