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3 years ago

Which of the following pairs of atoms do NOT exhibit an ionic bond?

Chemistry

2 answers:

Eddi Din [679]3 years ago

7 0

N and H are both gases and would not form an ionic bond.

Olegator [25]3 years ago

4 0

Answer:

F and Cu.

Explanation:

Hello,

In this case, by knowing that the farther the elements in the periodic table, the more ionic they are, in addition to the difference in the electronegativity which must be greater than 1.7 for the bond to be ionic, we can substantiate that the iron and the copper don't exhibit an ionic bond as shown below:

$\Delta E=E_{Cu}-E_{Fe}=1.9-1.83=0.07$

Such value is characteristic for covalent bonds.

Best regards.

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Elements that can be described by the hardness shininess and ductility

Eddi Din [679]

Metals. Titanium is very hard, gold is shiny, and copper is ductile(can be pulled into a wire without breaking).

6 0

3 years ago

1. In general, the nucleus of a small atom is stable. Therefore, over very short distances, such as those in a small nucleus,

postnew [5]

<h3>1. Answer;</h3>

a. the strong nuclear force is much greater than the electric force.

<h3>Explanation;</h3>

For an atom to be stable it means it has enough amount of binding energy to hold its nucleus together permanently.
Therefore, an unstable atom lacks enough amount of binding energy to hold its nucleus permanently and thus undergoes decay to achieve stability. Unstable atoms are therefore referred to being radioactive.
Small atoms are stable; this is because they have equal number of protons and neutrons and thus the protons and neutrons fill up energy levels while maximizing the strong force binding the nucleus together.

<h3>9. Answer;</h3>

b. change into a different element altogether.

Uranium-238 undergoes alpha decay. Therefore, uranium-238 will change into a different element altogether.

<h3> Explanation;</h3>

Unstable atoms undergo radioactive decay in order to achieve stability of their nucleus.
Uranium-238 is an example of such atom, which may undergo decay to achieve stability.
Alpha decay is one of the types of decays, others being beta decay and gamma decay. In alpha decay the radioactive isotope undergoes decay such that its mass number is decreased by four and its atomic number is decreased by two.
Therefore, Uranium-238 undergoes alpha decay to form a different element whose mass number is 234 and atomic number is 90, known as thorium-234.

5 0

3 years ago

Read 2 more answers

how do the properties of compounds compare to the properties of the elements from which they are composed

Crank

The elements that form the compound don't compare because it doesn't matter about the elements when they are combined. The elements that formed it together is completely different than the outcome compound.

6 0

3 years ago

0.5832 miles =____ft and ___ inches

arlik [135]

Answer:

0.5832 miles =3079ft and 3.552 inches

Explanation:

This is if you are wanting the foot amount and the extra in inches, if you are wanting it in just feet and just inches it would be 3079.296 feet and 36951.552 inches

3 0

3 years ago

A 1.68 g sample of water is injected into a closed evacuated 5.3 liter flask at 65°C. What percent (by mass) of the water will b

Angelina_Jolie [31]

Answer:

50.4 % of the water will be vapor

Explanation:

Step 1: Data given

Mass of water = 1.68 grams

volume of the flask = 5.3 L

Temperature = 65°C

Vapor pressure of water at 65°C = 187.5 mmHg = 0.2467 atm

Step 2: Calculate moles of H2O

p*V=n*R*T

⇒ p = the pressure of water = 0.2467 atm

⇒ V = the volume of the flask = 5.3 L

⇒ n = moles of water

⇒ R = gas constant = 0.08206 L*atm/ K*mol

⇒ T = the temperature = 65°C = 338 Kelvin

n = (p*V)/(R*T)

n = (0.2467 * 5.3) /(0.08206* 338)

n = 0.047 moles

Step 3: Calculate mass of water

Mass of water = moles of water * molar mass of water

Mass of water = 0.047 moles *18.02 g/mol

Mass of water = 0.84694 grams

Step 4: Calculate the percent of water vaporized

% = (0.84694 grams/1.68 grams) *100%

% = 50.4%

50.4 % of the water will be vapor

5 0

3 years ago