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Radda [10]
3 years ago
9

Tamaica can wrap 24 presents in 5 hours. how long will it take her to wrap 72 presents?

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
7 0

So for this you will be doing proportions, and in this case the equation will be \frac{24}{5} =\frac{72}{x}


Firstly, you will cross multiply. Your equation should look like this: 24x=360


After that, just divide 24 on each side and your answer will be x=15



In short, she can wrap 72 presents in 15 hours.

Nitella [24]3 years ago
5 0

it would take 15 hours to wrap 72 presents

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Answer:

yes

Step-by-step explanation:

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4 years ago
1-cos2a/1+cosa if 1/3 how much sin²a
Helen [10]

Answer:

(1-cos2A) /(1+cos2A) =tan²A

Proof:

We know that,

cos(A+B) =cosA.cosB-sinA.sinB

=>cos2A=cos(A+A)

=>cos2A=cosA.cosA - sinA.sinA

=>cos2A=cos²A-sin²A

=>cos2A=(cos²A-sin²A)/(cos²A+sin²A

Since {cos²A+sin²A=1}

Divide the numerator & the denominator by (cos²A) to get,

cos2A = {(cos²A-sin²A) ÷cos²A} / {(cos²A+sin²A) ÷cos²A}

cos2A ={(1-tan²A)/(1+tan²A)}

Then,

1-cos2A = 1-[{(1–tan²A)/(1+tan²A)}]

1-cos2A =(1+tan²A-1+tan²A)/(1+tan²A)

1-cos2A=(2tan²A)/(1+tan²A)

And now.......

1+cos2A=1+[{(1-tan²A)/(1+tan²A)}]

1+cos2A={1+tan²A+1-tan²A}/{1+tan²A}

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So now,

(1-cos2A)/(1+cos2A)= {2tan²A/(1+tan²A)}÷{2/(1+tan²A)}

={(2tan²A)(1+tan²A)}÷{2(1+tan²A)}

=tan²A

Step-by-step explanation:

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4 years ago
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3 years ago
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So the value of h is 9
8 0
3 years ago
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3 years ago
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