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valentina_108 [34]
4 years ago
6

What phenomenon distinguishes longitudinal waves from transverse waves?

Physics
1 answer:
Ad libitum [116K]4 years ago
7 0
"the direction of the force exerted by the wave" distinguishes <span> longitudinal waves from transverse waves

Hope this helps!</span>
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3 0
3 years ago
If the fly experienced a force of 100 N when it hits how big was the force on the vehicle in this collision
iogann1982 [59]

Answer:

100N

Explanation:

because newton's third law of motion states that if body A exerts a force on the body B, then Body B will exert an equal force but opposite in direction force on body A

so if the fly experienced 100N, then the car will also experience 100N

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8 0
4 years ago
Find the magnitude of u × v and the unit vector parrallel to u × v in the direction of u × v. u = 2i + 2j - k, v = -i + k
IrinaVladis [17]

Answer:

magnitude = 3

unit vector = \frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}

Explanation:

Given vectors:

u = 2i + 2j - k

v = -i + k = -i + 0j + k

(a) u x v is the cross product of u and v, and is given by;

u X v = \left[\begin{array}{ccc}i&j&k\\2&2&-1\\-1&0&1\end{array}\right]

u x v = i(2+0) - j(2 - 1) + k(0 - 2)

u x v = 2i - j - 2k

Now the magnitude of u x v is calculated as follows:

| u x v | = \sqrt{2^2 + (-1)^2 + (-2)^2}

| u x v | = \sqrt{4 + 1 + 4}

| u x v | = \sqrt{9}

| u x v | = 3

Therefore, the magnitude of u x v is 3

(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e

û = \frac{u X v}{|u X v|}        

u x v = 2i - j - 2k        [<em>calculated in (a) above</em>]

|u x v| = 3                   [<em>calculated in (a) above</em>]

∴ û = \frac{2i - j - 2k}{3}

∴ û = \frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}

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