A 5 kilogram block is dropped from a height of 3 meters and falls straight to the ground. What is the work done by the force of
1 answer:
Answer:
Workdone = 147Nm
Explanation:
Given the following data;
Mass = 5kg
Height = 3m
We know that acceleration due to gravity is 9.8m/s²
First of all, we would find the force applied;
Force = 5*9.8
Force = 49N
Now, to find the workdone;
Substituting into the equation, we have;
Workdone = 49 * 3
Workdone = 147Nm
You might be interested in
Answer:
m = 236212 [kg]
Explanation:
The potential energy can be determined by means of the product of mass by gravity by height. In this way, we have the following equation.
where:
P = potential energy = 3360000000 [J]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 1450 [m]
Now, we can clear the mass from the equation above:
Answer:
Induced emf,
Explanation:
Given that,
Length of the helicopter, l = 4 m
Angular speed of the helicopter,
The vertical component of the Earth’s magnetic field is,
We need to find the induced emf between the tip of a blade and the hub. The induced emf in terms of angular velocity of an rotating object is given by :
So, the induced emf between the tip of a blade and the hub is . Hence, this is the required solution.