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3 years ago

Light-colored objects have high albedo because they have high reflectivity of sunlight. True or False

Physics

2 answers:

s344n2d4d5 [400]3 years ago

8 0

Answer:

I would say true

Elina [12.6K]3 years ago

3 0

Answer: Its true

Explanation:

Bright, reflective surfaces have a high albedo .

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A vehicle moving along at 5m/s. What should be the constant deceleration in order to stop it within 15m?

Oduvanchick [21]

Answer:

a = -5/6 m/s²

Explanation:

v² = u² + 2as

a = (v² - u²) / 2s

a = (0² - 5²) / 2(15)

a = -5/6 m/s²

This assumes the initial velocity was in the positive direction.

5 0

3 years ago

Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride.

Mashcka [7]

The amount of work which Sam does need to stop the boat is 784Joule if boat mass is 800kg and boat drift in 1.4m/sec.

We know that according to work-energy theorem, change in kinetic energy of the body from one speed to another is equivalent to amount of work done by all forces acting on the body.

So, here we can see that final speed of boat is =0m/sec since Sam need to stop it.

Initial speed of boat is 1.4m/sec.

Also, we know that kinetic energy is given by the below formula:

Kinetic energy=(1/2)mv²

where m is the mass of the body

and v is the speed of the body

Now, from work energy theorem, we get

=>W=(1/2)m $v^2_2$ - (1/2)m $v^2_1$

=>W=0-(1/2)×800×(1.4)²

=>W= - 400× 1.4 × 1.4

=>W = -400×1.96

=>W= -784Joule

Here negative sign denotes work has to done against the original motion of boat.

Hence, amount of work needs to be done by Sam is 784Joule.

To know more about work,visit here:

brainly.com/question/18094932

#SPJ4

3 0

1 year ago

The blades of a metal cutter are shorter than the blades of paper cutter scissor. Give reason

Sladkaya [172]

Answer:

Metal is a tougher material to cut though, so the blades must be shorter to create more pressure to break through the metal. Paper on the other hand is easier to cut through so the blades can be longer in order to cut more in each snip.

8 0

3 years ago

An object is inside a room that has a constant temperature of 292 K. Via radiation, the object emits three times as much power a

maw [93]

Answer: Maybe he has the heater on

Explanation: If there is that much temperature then it has to be from something heated.

8 0

3 years ago

Consider two laboratory carts of different masses but identical kinetic energies and the three following statements. I. The one

kolbaska11 [484]

Answer:

d) I and III only.

Explanation:

Let be $m_{1}$ and $m_{2}$ the masses of the two laboratory carts and let suppose that $m_{1} > m_{2}$ . The expressions for each kinetic energy are, respectively:

$K = \frac{1}{2}\cdot m_{1}\cdot v_{1}^{2}$ and $K = \frac{1}{2}\cdot m_{2}\cdot v_{2}^{2}$ .

After some algebraic manipulation, the following relation is constructed:

$\frac{m_{1}}{m_{2}} = \left(\frac{v_{2}}{v_{1}}\right)^{2}$

Since $\frac{m_{1}}{m_{2}} > 1$ , then $\frac{v_{2}}{v_{1}} > 1$ . That is to say, $v_{1} < v_{2}$ .

The expressions for each linear momentum are, respectively:

$p_{1} = \frac{2\cdot K}{v_{1}} = m_{1}\cdot v_{1}$ and $p_{2} = \frac{2\cdot K}{v_{2}} = m_{2}\cdot v_{2}$

Since $v_{1} < v_{2}$ , then $p_{1} > p_{2}$ . Which proves that statement I is true.

According to the Impulse Theorem, the impulse needed by cart I is greater than impulse needed by cart II, which proves that statement II is false.

According to the Work-Energy Theorem, both carts need the same amount of work to stop them. Which proves that statement III is true.

6 0

3 years ago