Answer:
I would suggest he decrease the sales price.
Explanation:
Because it will might make people rush the product due to its low price compared to other products of another brand.
The low price will create a high demand for the product therefore causing the quantity of the products being produced to increase.
The quality of the product will be very good since the quality is not being reduced only the price therefore it might result in not having the maximum profit needed.
Drug Abuse Resistance Education (D.A.R.E.) is a police officer-led arrangement of classroom exercises that shows kids (normally in rudimentary or center school) how to remain tranquilize free and oppose peer weight.
According to Rosenbaum and Hanson (1998), D.A.R.E has no critical in general effect on utilizing cigarettes or liquor
They concluded that, Given the tremendous uses in time and cash required with D.A.R.E., no doubt proceeded with endeavors should center around different systems and projects that may deliver more significant impacts.
Answer:
The maturity value is "$79790".
Explanation:
The given values are:
Principal
= $79,000
Time
= 30/360
Rate
= 12%
The interest on the cash loan to Ryan and Co will be:
= 
= 
($)
Maturity value
= 
= 
= 
= 
Answer:
B. Credit to sales revenue
Explanation:
As per revenue recognition principle, revenue should be recognized when it is earned and not when cash is received.
As per accrual basis of accounting, revenue is to be recognized when the ownership of the goods has been passed by the seller to the buyer and there is reasonable assurance that payment would be received.
When a sale is effected and goods are delivered with reasonable certainty that payment would be received, following journal entry is recorded:
Accounts Receivable A/C Dr.
To Sales Revenue
(Being equipment sold recorded)
Answer:
E = 1.20 × 
N/C
V = 1800 V
x = 0.058 m
Explanation:
given data
radius = 15 cm
net charge = 3 × 
C
electric potential decreased = 500 V
solution
we get here electric field at the sphere’s surface that is
electric field at the sphere’s surface E = 
............1
put here value
electric field at the sphere’s surface E = 
E = 1.20 × N/C
and
potential on surface of sphere is
V = 
................2
V = 
V = 1800 V
and
now we get distance that is x
and we know here
ΔV = V(x) - V ..............3
substitute here value
-500V = 
-500 V = 
solve it we get x
x = 0.058 m
