Answer:
2.23 Hz
Explanation:
From the attached diagram below; there exists a diagrammatic representation of the equilibrium position of the cylinder.
The equilibrium position of the spring is expressed as:
mg = K
where;
m = mass of the object
g = acceleration due to gravity
K = spring constant
= static deflection of the string
Given that:
m = 30 kg
g = 9.81 m/s²
= 50 mm = 50 × 
= 0.05 m
Then;
From here; let us find the angular velocity which will be needed to determine the natural frequency aftewards.
The angular velocity of the cylinder can be expressed by the formula:
Finally; the natural frequency 
can be calculated by using the equation
= 2.229305729
≅ 2.23 Hz
Thus; the resulting natural frequency of the vertical vibration of the cylinder = 2.23 Hz
Answer:
(a)= 264mmHg
(b)= 2000mmHg
(c)474.82mmHg
(d)= 511.63mmHg
Explanation:
the question deals with boyles law, which states that the volume of a given mass of gas at constant temperature is inversely proportional to its pressure
V ∝ 1/P
P₁V₁ = P₂V₂
making V₂ as the subject of formular
P₂ = P₁V₁/ V₂
with a volume of 25.0L
P₂ = 660×10 / 25
= 264mmHg
with a volume of 3.30 L
P₂ = 660 × 10 / 3.30
= 2000mmHg
with a volume of 13900 mL
= 13.9L
P₂ =660× 10 / 13.9
474.82mmHg
with a volume of 12900 mL
P₂ =660×10 / 12.9
= 511.63mmHg
The answer would be Power
1 is amplitude crest is 5 3 is wavelength. Your chart is confusing so that’s all I got
Hiya!
The answer to your question is B.
Physical Properties.
~Hope this helps~
