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4 years ago

How are the helium atoms in this model different from real helium atoms?

Physics

2 answers:

Taya2010 [7]4 years ago

5 0

Answer;

Real helium atoms are too small to see

Explanation;

-A helium atom is an atom of the chemical element helium.

-Helium is composed of two electrons bound by the electromagnetic force to a nucleus containing two protons along with either one or two neutrons, depending on the isotope, held together by the strong force.

KonstantinChe [14]4 years ago

3 0

With the information given in the question, we can only observe
that they are quite SIMILAR in at least one respect ... both the real
ones and those in 'this model' are quite invisible and intangible, and
we must take your word for it that they exist at all.

Like so many others in math and science, this question raises another
question: "Which model are you talking about ?"

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A train travelled 500 meters in 25 seconds

KIM [24]

$\huge\mathfrak\red {Answer:}$

<h2>Speed = Distance/Time</h2>

If a train travelled 500 meters in 25 seconds then,

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3 years ago

Read 2 more answers

A double charged ion is accelerated to an energy of 32.0 keV by the electric field between two parallel conducting plates separa

Zanzabum

Answer:

$E=8*10^5\frac{V}{m}$

Explanation:

The magnitude of the electric field between two parallel conducting plates is defined as:

$E=\frac{\Delta V}{d}$

Here $\Delta V$ is the potential difference between the plates and d its separation.

The electric potential energy is defined as the product between the particle's charge and the potential difference:

$U=q\Delta V$

Solving for $\Delta V$ and replacing in the electric field formula:

$\Delta V=\frac{U}{q}\\E=\frac{U}{qd}$

In this case we have a double charged ion, so $q=2e$ :

$E=\frac{32*10^3eV}{(2e)(2*10^{-2}m)}\\E=8*10^5\frac{V}{m}$

6 0

3 years ago

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A

ArbitrLikvidat [17]

Answer:

The mass of the solid cylinder is $m = 1612.5 \ kg$

Explanation:

From the question we are told that

The radius of the grinding wheel is $R = 0.330 \ m$

The tangential force is $F_t = 250 \ N$

The angular acceleration is $\alpha = 0.940 \ rad/s^2$

The torque experienced by the wheel is mathematically represented as

$\tau = I * \alpha$

Where I is the moment of inertia

The torque experienced by the wheel can also be mathematically represented as

$\tau = F_t * r$

substituting values

$\tau = 250 * 0.330$

$\tau = 82.5 \ N\cdot m$

$82.5 = I * \alpha$

$82.5 = I * 0.940$

$I = 87.8 \ kg \cdot m^2$

This moment of inertia can be mathematically evaluated as

$I = \frac{1}{2} * m* r^2$

substituting values

$87.8 = \frac{1}{2} * m* (0.330)^2$

=> $m = 1612.5 \ kg$

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3 years ago

In football we see unbalanced forces. When 1 player exerts an unbalanced force on another player and causes a player to

zaharov [31]

Answer:

Fall

Explanation:

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3 years ago

Is a hotdog a sandwich? Why or Why not?

Wewaii [24]

Answer:

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3 years ago