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Sphinxa [80]
3 years ago
7

5.8 meters/second + 1.2 meters/second

Physics
2 answers:
Alex Ar [27]3 years ago
8 0

Answer:7m/s

Explanation:

5.8+1.2

=7.

Natali5045456 [20]3 years ago
4 0
7 i have done this before
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a stone is thrown by a person from the top of the building, which is 200m tall. at the same time, another stone is thrown with v
solniwko [45]

Answer:

The time after which the two stones meet is tₓ = 4 s

Explanation:

Given data,

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Using the II equation of motion

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Let tₓ be the time where the two stones  meet and x be the distance covered from the top of the building

The equation for the stone dropped from top of the building becomes

                            x = 0 + ½ gtₓ²

The equation for the stone thrown from the base becomes

                S - x = U tₓ - ½ gtₓ²  (∵ the motion of the stone is in opposite direction)

Adding these two equations,

                      x + (S - x) = U tₓ

                               S = U tₓ

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∴                                  tₓ = 4 s

Hence, the time after which the two stones meet is tₓ = 4 s   

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