Let's take east and west to be positive and negative, respectively, and north and south to be positive and negative, respectively. Then in terms of vectors (using ijk notation), the car first moves 200 km west,
<em>r</em> = (-200 km) <em>j</em>
then 80 km southwest,
<em>s</em> = (-80/√2 km) <em>i</em> + (-80/√2 km) <em>j</em>
so that its total displacement is
<em>r</em> + <em>s</em> = (-80/√2 km) <em>i</em> + ((-200 - 80/√2) km) <em>j</em>
<em>r</em> + <em>s</em> ≈ (-56.6 km) <em>i</em> + (-256.6 km) <em>j</em>
This vector has magnitude
√((-56.6 km)² + (-256.6 km)²) ≈ 262.7 km
and direction <em>θ</em> such that
tan(<em>θ</em>) = (-256.6 km) / (-56.6 km) ==> <em>θ</em> ≈ -102.4º
relative to east, or about 12.4º west of south.
9.5+3.5+15 m in 43 secs
28m in 43 secs
28/43 m/s
total distance/total time=av speed
Answer:
serial in which container is filled
Solid -base of container
Liquid- above solid
Gas- above liquid
Explanation:
If any mixture of matter in different state (that solid , liquid or gas )are kept in any container, then substance with higher density will be settled at lowest surface first and similarly the substance with lowest density will be at upper part of container.
In the given container we have to keep solid, liquid and gas
- sold has the highest density,
- gas the lowest density and
- liquid has the density higher than gas but less than solid.
based on this
solid will be at surface of container
above sold will be liquid
above liquid will be presence of Gas
serial in which container is filled
Solid -base of container
Liquid- above solid
Gas- above liquid
A combination of one hydrogen atom and 2 oxygen atoms.
Answer: D) It should be handled in a fume hood, away from open flames.