Graphically determine the resultant of the following three vector displacements: (1) 34 m, 25º north of east; (2) 48 m, 33° east
of north; and (3) 22 m, 56° west of south.
1 answer:
Answer:
Explanation:
In the first attached image, we can see, the nomenclature used for Angle orientations.
To sum the vectors we must join the head of one of them with the tail of the next, at the end joins the tail of the first vector with the head of the last vector.
In the second attached image, we can find graphically the sum of each of the vectors.
The resultant vector has a length of 57.36[m], and goes 48° north of east.
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Answer:
the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s
Explanation:
Pitot tube
U = velocity(m/s)
= stagnation pressure (pa)
= static pressure (pa)
d = fluid density(kg/m³)
v = true velocity
= 101325 + 1/2(1.225)(25)²
d = 1.225kg/m³
the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s