The mass is moving with an acceleration of 13.299 m/s².
<h3>What is the straight forward meaning of acceleration?</h3>
The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations.
According to therefore mentioned statement,
the direction of the net force applied on an object determines its acceleration;
according to mentioned data;
F₁=30N
F₂=10N
Net force on object;
F=F₁+F₂
F=F₁y+F₂Cos30°(-x)+F₂ Sinx(-y)
F=3y+10×(√3/2)(-x)+10×(1/2)(-y)
F=ma
ma=-5√3/2(x)+25y
2a=-5√3x/2+25y
a=-5√3x+25y
magnitude(a)=√(-5√3/2)²+(25/2)²
(a) =13.299m/s²
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I think it would be eager
A circuit with an impedance of 5 ohms and a voltage of 100 volts has a current flow of 20 A.
The expression of an electronic component, circuit, or system's resistance to alternating and/or direct electric current is called impedance, indicated by the letter Z. Resistance and reactance are two distinct scalar (one-dimensional) phenomena that combine to form impedance, a vector (two-dimensional) variable.
= 
(for a pure resistor where Z=R,preserving the form of the DC Ohm's law).
I = 20 A
Therefore, A circuit with an impedance of 5 ohms and a voltage of 100 volts has a current flow of 20 A.
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Acceleration=9.81m/s^2
initial velocity=0m/s
time=.28s
We have to find final velocity.
The equation we use is
Final velocity=initial velocity+acceleration x time
Vf=0m/s+(9.81m/s^2)(.28s)
Vf=2.7468m/s
We would round this to:
Vf (final velocity)=2.7m/s
Answer:
a) F₁₂₀ = 1.34 pa A , b) F₂₀ = 0.746 pa A
Explanation:
Part. A
. The definition of pressure is
P = F / A
As the air can approach an ideal gas we can use the ideal gas equation
P V = n R T
Let's write this equation for two temperatures
P₁ V = n R T₁
P₂2 V = n R T₂
P₁ / P₂ = T₁ / T₂
point 1 has a pressure of P₁ = pa and a temperature of (20 + 273) K, point 2 is at (120 + 273) K, we calculate the pressure P₂
P₂ = P₁ T₂ / T₁
P₂ = pa 393/293
P₂ = 1.34 pa
We calculate the strength
P₂ = F₁₂₀ / A
F₁₂₀ = 1.34 pa A
Part B
In this case the data is
Point 1 has a temperature of 393K and an atmospheric pressure (P₁ = pa), point 2 has a temperature of 293K, let's calculate its pressure
P₁ / P₂ = T₁ / T₂
P₂ = P₁ T₂ / T₁
P₂ = pa 293/393
P₂ = 0.746 pa
Let's calculate the force (F20), from this point
F₂₀ / A = 0.746 pa
F₂₀ = 0.746 pa A
