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Rina8888 [55]
3 years ago
8

A train travelled 500 meters in 25 seconds

Physics
2 answers:
KIM [24]3 years ago
7 0

\huge\mathfrak\red {Answer:}

<h2>Speed = Distance/Time</h2>

If a train travelled 500 meters in 25 seconds then,

Speed = 500m/25sec

<h2>→ 20 m/sec</h2>

\mathfrak\purple {Hope\: this\: helps\: you...}

Radda [10]3 years ago
7 0

speed=500m/25sec

20m/sec

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A motorist drives north for 35.0 minutes at 85.0 kph. He then stops for 15.0 minutes. The motorist then drives 130.0 km in 2.0 h
o-na [289]

Answer:

A. 216.36 \frac{km}{h}

B. 96.56 \frac{km}{h}

Explanation:

Let s_{1} be the distance in first part.

s_{1} = velocity × time

s_{1} = 85 × \frac{35}{60}

s_{1} = 49.58 km

Let s_{2} be the distance in first part.

s_{2} = 130 km

Average velocity = \frac{Total displacement}{Total time}

When second leg of the trip is

A. Toward north

Average velocity = \frac{[tex] s_{1} + s_{2}}{Total time}  [/tex]

Average velocity = \frac{130+49.58}{0.25+0.58}

Average velocity =216.36 \frac{km}{h}

B. Toward south

Average velocity = \frac{[tex] s_{1} - s_{2}}{Total time}  [/tex]

Average velocity = \frac{130-49.58}{0.25+0.58}

Average velocity =96.56 \frac{km}{h}


3 0
3 years ago
On a visit to a science lab, Madison observes a blob of shiny material that is floating in the air.
AfilCa [17]

Answer:

Each force acting on the blob has another one to cancel it out

Explanation:

7 0
3 years ago
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What is the speed of a 16 cm wave with a period of 8 seconds?
sp2606 [1]

The speed of a 16cm wave with a period of 8 seconds is 2cm/s

<h3>How to determine the speed</h3>

Using the formula;

Speed = distance ÷ time

Distance = 16cm

time = 8 seconds

Substitute into the formula

Speed = 16 ÷ 8

Speed = 2 cm/s

Therefore, the speed of a 16cm wave with a period of 8 seconds is 2cm/s

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2 years ago
The particle starts from rest at t=0. What is the magnitude p of the momentum of the particle at time t? Assume that t&gt;0. Exp
olganol [36]

Answer:

Ft

Explanation:

We are given that

Initial velocity=u=0

We have to find the magnitude of p of the momentum of the particle at time t.

Let mass of particle=m

Applied force=F

Acceleration, a=\frac{F}{m}

Final velocity , v=a+ut

Substitute the values

v=0+\frac{F}{m}t=\frac{F}{m}t

We know that

Momentum, p=mv

Using the formula

p=m\times \frac{F}{m}t=Ft

6 0
4 years ago
A 50 V source is attached to a 9 Ohm light bulb, a 15 Ohm resistor, and a 17 Ohm resistor. What is the total resistance in the c
4vir4ik [10]

Answer:

41

Explanation:

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