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2 years ago

A train travelled 500 meters in 25 seconds

Physics

2 answers:

KIM [24]2 years ago

7 0

$\huge\mathfrak\red {Answer:}$

<h2>Speed = Distance/Time</h2>

If a train travelled 500 meters in 25 seconds then,

Speed = 500m/25sec

$\mathfrak\purple {Hope\: this\: helps\: you...}$

Radda [10]2 years ago

7 0

speed=500m/25sec

20m/sec

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three girls were pushing the same car with a net force of 450 N [N48°E]. Two of the girls were pushing with forces of 310 N [N25

ElenaW [278]

The net force is the vector

∑ F = (450 N) (cos(42°) i + sin(42°) j)

and two of the forces provided by the girls are

F₁ = (310 N) (cos(115°) i + sin(115°) j)

F₂ = (250 N) (cos(285°) i + sin(285°) j)

Then the force provided by the third girl is the vector

F₃ = ∑ F - F₁ - F₂

F₃ = ((450 N) cos(42°) - (310 N) cos(115°) - (250 N) cos(285°)) i

… … … + ((450 N) sin(42°) - (310 N) sin(115°) - (250 N) sin(285°)) j

F₃ ≈ (400.722 N) i + (261.635 N) j

So, the third girl provided a force of magnitude

||F₃|| = √((400.722 N)² + (261.635 N)²) ≈ 478.572 N ≈ 480 N

pointing in a direction

arctan((261.635 N)/(400.722 N)) ≈ 33.1409° ≈ 33°

relative to East which refers to 0°; that is, 33° N of E or E33°N. Since the other forces are given relative to North or South, we can write this direction as N57°E.

So, the third girl pushed with force 480 N [N57°E].

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2 years ago

A current of 0.92 A flows past a point in a circuit? How much charge, in units of Coulombs, passes that point in one minute?

Alisiya [41]

<h3><u>Answer;</u></h3>

<u> = 55.2 Coulombs </u>

<h3><u>Explanation</u>;</h3>

We can determine Charge using the formula

Q =It, where Q is the amount of charge in Coulombs, I is the current in amperes and t is the time in seconds.

I = 0.92 amperes, t = 1 minute or 60 seconds

Charge = 0.92 × 60

<u> = 55.2 Coulombs </u>

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Answer:

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Answer:

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3 years ago