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Sergio039 [100]
2 years ago
15

A double charged ion is accelerated to an energy of 32.0 keV by the electric field between two parallel conducting plates separa

ted by 2.00 cm. What is the electric field strength between the plates?
Physics
1 answer:
Zanzabum2 years ago
6 0

Answer:

E=8*10^5\frac{V}{m}

Explanation:

The magnitude of the electric field between two parallel conducting plates is defined as:

E=\frac{\Delta V}{d}

Here \Delta V is the potential difference between the plates and d its separation.

The electric potential energy is defined as the product between the particle's charge and the potential difference:

U=q\Delta V

Solving for \Delta V and replacing in the electric field formula:

\Delta V=\frac{U}{q}\\E=\frac{U}{qd}

In this case we have a double charged ion, so q=2e:

E=\frac{32*10^3eV}{(2e)(2*10^{-2}m)}\\E=8*10^5\frac{V}{m}

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Two parallel wires separated by a distance of 0.6 m each carry current in the same direction. One wire is carrying a current of
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Answer:

The value is  B =  3.33 *10^{-6} \  T

Explanation:

From the question we are told that

  The distance of separation is  d = 0.6 \  m

  The current on the one wire is I_1 =  9 \  A

  The current on the second wire is I_2 =  4 \ A

Generally the magnitude of the field exerted between the current carrying wire is

        B  =  B_1 - B_2

Here B_1 is the magnetic field due to the first wire which is mathematically represented as

         B_1 = \frac{\mu_o * I_1 }{2 \pi * d_1}

Here d_1 is the distance to the half way point of the separation and the value is  

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B_2 is the magnetic field due to the first wire which is mathematically represented as

         B_2  = \frac{\mu_o * I_2 }{2 \pi * d_2}

Here d_2 is the distance to the half way point of the separation and the value is  

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This means that d_1 = d_2 = a =  0.3

So

     B =  \frac{\mu_o * I_1 }{2 \pi * d_1}  -  \frac{\mu_o * I_2 }{2 \pi * d_2}

=>  B =  \frac{\mu_o * (I_1 - I_2)}{2 \pi *0.3 }

=>  B =  \frac{  4\pi * 10^{-7}  * (9- 4)}{2 * 3.142  *0.3 }

=>  B =  3.33 *10^{-6} \  T

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