What's the symbol for an ionized gallium atom?
1 answer:
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The figure mentioned on the question is in the attachment.
Answer: a) = - 38.35N
b) = 30.5 N
c) = 27.45 N
d) a = - 13.16 m/s²
Explanation: A block on an inclined plane has 3 forces acting on it:
- Force due to gravity
= m.g;
- Normal Force due to the plane;
- Force of Friction
= µ.N;
Since the plane is inclined, Normal Force is equal the y-component of the force due to gravity and Force of friction and the x-component of the force due to gravity are opposite forces.
The second attachment ilustrate the forces acting on the block.
Calculating:
A) The magnitude of the x-component of Force due to gravity:
According to the second image:
= P.sinθ
= 5.9.8.sin(36.8)
= - 38.35 N
B) =
= m.g.cosθ
= 5.9.8.cos(36.8)
= 30.5 N
C) = 0.9.30.5
= 27.45 N
D) For the acceleration, use Newton's Law: = m . a
If there is movement, it is only on x-axis, so the net force is:
-
= m.a
- 38.35 - 27.45 = 5a
a = - 13.16 m/s²
The value of acceleration shows there is <u>no</u> <u>movement</u> on the x-axis due to the friction.
