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andrew11 [14]
3 years ago
6

At the local playground, a 21-kg child sits on the right end of a horizontal teeter-totter, 1.8 m from the pivot point. On the l

eft side of the pivot an adult pushes straight down on the teeter-totter with a force of 151 N.In which direction does the teeter-totter rotate if the adult applies the force at a distance of 3.0 m from the pivot? (clockwise/ counterclockwise)

Physics
2 answers:
Novosadov [1.4K]3 years ago
8 0

The teeter-totter rotates counterclockwise

\texttt{ }

<h3>Further explanation</h3>

<em>Let's recall </em><em>Moment of Force</em><em> as follows:</em>

\boxed {\tau = F d }

<em>where:</em>

<em>τ = moment of force ( Nm )</em>

<em>F = magnitude of force ( N )</em>

<em>d = perpendicular distance between force and pivot ( m )</em>

Let us now tackle the problem !

<u>Given:</u>

mass of child = m_c = 21 kg

distance between pivot and child = d_c = 1.8 m

magnitude of force = F = 151 N

distance between force and pivot = d = 3.0 m

<u>Asked:</u>

direction of rotation = ?

<u>Solution:</u>

<em>Firstly , we will find </em><em>clockwise moment</em><em> by weight of the child:</em>

\tau_{clockwise} = w \times d_c

\tau_{clockwise} = mg \times d_c

\tau_{clockwise} = ( 21 \times 9.8 ) \times 1.8

\boxed{\tau_{clockwise} = 370.44 \texttt{ Nm}}

\texttt{ }

<em>Next, we will find </em><em>counterclockwise moment </em><em>by pushing force:</em>

\tau_{counterclockwise} = F \times d

\tau_{counterclockwise} = 151 \times 3.0

\boxed{\tau_{counterclockwise} = 453 \texttt{ Nm}}

\texttt{ }

<h3>Conclusion:</h3>

\tau_{counterclockwise} > \tau_{clockwise}

\texttt{The teeter-totter rotates \boxed{counterclockwise}}

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Moment of Force

Alja [10]3 years ago
3 0

Answer:

Counterclockwise

Explanation:

We need to calculate the clocwkise and the counterclockwise torque.

The clockwise torque is the one generated by the child sitting on the right. This torque is given by:

M_C = F d

where

F=mg=(21 kg)(9.8 m/s^2)=205.8 N is the force exerted by the child (his weight)

d = 1.8 m is the distance from the pivot point

So, the clockwise torque is

M_C = (205.8 N)(1.8 m)=370.4 Nm

The counterclockwise torque is the one generated by the adult pushing on the left, and it is given by

M_A = F d

where

F = 151 N is the force applied

d = 3.0 m is the distance from the pivot

Substituting,

M_A = (151 N)(3.0 m)=453 Nm

So, the net torque is

M_A - M_C = 453 Nm - 370.4 Nm=82.6 Nm

And since the counterclockwise momentum is greater than the clockwise one, the teeter-totter will rotate counterclockwise.

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