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anastassius [24]
2 years ago
9

In a polytropic process, with the exponent n = k, where k is the specific heat ratio, 1.0 kg of neon (an ideal gas) in a frictio

n-free piston-cylinder assembly expands from 400 k and 500 kpa to 100 kpa. for neon, ne = 20.18 kg/kmol and k = 5/3. sketch the system and the process. previously, you should have evaluated the work done by the gas in this process = _________ kj now find the final temperature of the gas (using the polytropic formulas for ideal gases), and then find the change in internal energy for the process = ___________ kj
Physics
1 answer:
Elden [556K]2 years ago
3 0
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
Read more on Brainly.com - brainly.com/question/1581851#readmore
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The dispatcher of courier service receives a message from truck A that reports a position of +5 after a displacement of +2. What
Romashka [77]

The formula we need to use is displacement.

d=\Delta{x}=x_f-x_i, where xf is final position and xi is initial position.

We report the final position of 5 and the displacement of 2 so the formula is now:

2=5-x_i\Longrightarrow x_i=3.

So the initial position of truck A is 3.

Hope this helps.

r3t40

8 0
2 years ago
The Venn diagram compares protons with neutrons. Which shared property belongs in the region marked "B"?
telo118 [61]

is there any choices?

4 0
3 years ago
Read 2 more answers
An organ pipe is made to play a low note at 27.5 Hz, the same as the lowest note on a piano. Assuming a sound speed of 343 m/s,
timama [110]

Answer:

The length of open-open pipe needed is 6.23 m

The length of open-close  pipe needed is 3.11 m

Explanation:

Fundamental frequency for standing wave mode of  an open- open pipe is given by

f=\frac{v}{2L}

where v is the velocity and L is the length

The length of open-open pipe needed is

L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m

Fundamental frequency for standing wave mode of  an open- close pipe is given by

f=\frac{v}{2L}

The length of open-close pipe needed is

L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m

7 0
3 years ago
A 19 kg child is riding a 5.6 kg bike with a
icang [17]

Answer:

\mathrm{a.\:}123\:\mathrm{kg\cdot m/s},\\\mathrm{b.\:}95\:\mathrm{kg\cdot m/s},\\\mathrm{c.\:}28\:\mathrm{kg\cdot m/s}

Explanation:

The momentum of an object is given by:

p=mv, where m is the mass of the object and v is the velocity of the object.

a)

The mass of the child and bike together is 19+5.6=24.6 kilograms. Since they're moving at a velocity of 5.0 m/s, their momentum is:

p=24.6\cdot 5=\fbox{$123\:\mathrm{kg\cdot m/s}$}.

b)

The mass of the child is given as 19 kg. Since the child is on the bike moving at 5.0 m/s, it's implied the child is as well. Therefore, the momentum of the child is:

p=19\cdot 5=\fbox{$95\:\mathrm{kg\cdot m/s}$}.

c) The mass of the bike is given as 5.6 kg and it is moving at 5.0 m/s. Therefore, the momentum of the bike is:

<u />p=5.6\cdot 5=\fbox{$28\:\mathrm{kg\cdot m/s}$}<u />

4 0
3 years ago
Please help !! ASAP
umka2103 [35]

Answer:

22) 5.6 Kg.m/s

23) 0.067 Kg

24) 1.16 m/s

Explanation:

Momentum is found by multiplying mass and velocity

P=mv where P is momentum, m is mass of object and v is the velocity

22

Given

Mass, m=2 Kg

Rate, v=2.8 m/s

Relationship

P=mv

Solution

P=mv=2*2.8=5.6 Kg.m/s

23

Given

Momentum, p=0.1 Kg.m/s

Rate, v=1.5 m/s

Relationship

P=mv and making m the subject then

m=\frac {P}{v}

Solution

m=\frac {0.1 Kgm.s}{1.5 m/s}\approx 0.067 Kg

24

Given

Momentum, p=4.9\times 10^{8} Kg.m/s

Mass, m=4.23\times10^{8} Kg

Relationship

P=mv and making v the subject then

v=\frac {P}{m}

Solution

m=\frac {4.9\times 10^{8}  Kgm.s}{4.23\times10^{8} }\approx 1.16 m/s

5 0
2 years ago
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