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svet-max [94.6K]
3 years ago
9

1. Find the value for a/b=2 But make each side have the same value.

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

Step-by-step explanation:

a/b=662

a%chess issues

8=a/b equals exponent

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HELP ASAP PLEASE!!!! <br> EXTRA POINTS!!
uysha [10]
The answers are A, B, and D because to find the percent, you would have to multiply the percent by the number you're trying to get out of. There are different but correct ways written in A, B, and D.
8 0
3 years ago
Steven sold two less boxes of candy for the school fundraiser than Rodney with some of the boxes they sold with 8 how many boxes
wel
If Steven sold two boxes of candy less than Rodney and they sold 8 boxes, you can calculate how many boxes did each sell using the following steps:

Steven ... s = r - 2
Rodney ... r

s + r = 8
r - 2 + r = 8
2 * r = 8 + 2
2 * r = 10    /2
r = 5

s = r - 2 = 5 - 2 = 3

Result: Steven sold 3 boxes of candy and Rodney sold 5 boxes of candy.
7 0
3 years ago
What is 2 + 2, times 12, plus 9, divided by 1200, multiplied by 6, minus 12,000,000, divided by 4, plus 26, times 9, times 8, ti
vredina [299]

Answer:

78638.045 I hope this helped



8 0
3 years ago
Please help simplify the problem
galina1969 [7]

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8 0
3 years ago
Read 2 more answers
Please help me with the below question.
tresset_1 [31]

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.  

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

8 0
2 years ago
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