The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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Answer:
y = 5x - 7
Step-by-step explanation:
Using the equation of a line with two points
y_2 - y_1 / x_2 - x_1 = y - y_1 / x - x_1
Giving two points
( -4 , 10)(16 , -2)
x_1 = -4
y_1 = 10
x_2 = 16
y_2 = -2
Using the above formula
y_2 - y_1 / x_2 - x_1 = y - y_1 / x - x_1
-12 - 3 / -1 - 2 = y - 3 / x - 2
-15/-3 = y - 3 /x - 2
Cross multiply
-15(x - 2) = -3(y - 3)
-15x + 30 = -3y + 9
-15x + 30 + 3y - 9 = 0
-15x +30 - 9 + 3y = 0
-15x + 21 + 3y = 0
3y = 15x - 21 ( following y = mx + C
Dividing through by 3 to find y
3y/3 = 15x -21 / 3
y = 15x - 21 / 3
We can still separate
y = 15x / 3 - 21/3
y = 5x - 7
Therefore, the equation of the line is
y = 5x - 7
Answer:
4
Step-by-step explanation:when you put your in a toaster it leaves a mark
Answer:
200 tiles
Step-by-step explanation:
area of the floor = 2m×4m
the tile=20cm×20cm
the tiles needed to complete the job will be
2m×4m
——–—–
20cm×20cm
change the meters to centimeters
200cm×400cm
————————
20cm×20cm
therefore the answer is 200tiles.
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- A 3 dimensional figure with 5 sides
- it has 3 rectangles with dimensions 28 ft and 25 ft
- And 2 triangles with base =30 ft and height = 20 ft
- Total surface area of figure
ㅤ
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❒ Area of given figure
