The answer is true. There are more than one balance used in labs.
Answer:
The DNA sequence TTT TCG CGA TAT GCT GGT codes for the following amino acids: PHE-SER-ARG-TYR-ALA-GLY.
Protein Chain 1 is a substitution. The nucleotide at position 10 (T) is changed into a G resulting in the following DNA sequence: TTT TCG CGA GAT GCT GGT. The amino acid TYR is then changed into an ASP.
Protein Chain 2 is a deletion. The nucleotide at position 10 (T) is deleted and the resulting DNA sequence is TTT TCG CGA ATG CTG GT. There is then a different reading frame after nucleotide 9, which causes the amino acid sequence to change after the ARG.
Protein Chain 3 is an insertion (addition). After nucleotide at position 9, a C is added resulting in the following DNA sequence TTT TCG CGA CTA TGC TGG T. There is, as for protein chain 2, a different reading frame after nucleotide 9, which causes the amino acid sequence to change after the ARG.
Idk for sure but D is the only one that might make sense.
Hope this helps!
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Answer:
With a BB homozygous the probability of a gamete having the B allele is 100%, and no chance of having the b allele.
Explanation:
For a given trait, B represents the dominant allele, while b is the recessive one. The fact that an individual has a homozygous (dominant) form for this trait means that their homologous chromosomes contain the B allele and, therefore, his gametes can only have the B allele.
In the case that the individual was heterozygous, the chances of having a gamete with B or b would be 50:50.
Learn more:
Homologous chromosomes with heterozygous or homozygous alleles brainly.com/question/210889
