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lapo4ka [179]
3 years ago
9

How many molecules of NH3 are produced from 8.01x10-4g of H2

Chemistry
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

1.61 x 10²⁰ molecules

Explanation:

Given parameters:

Mass of the hydrogen gas  = 8.01 x 10⁻⁴g

Unknown

Number of molecules of NH₃ = ?

Solution:

Given reaction:

                     N₂  +  3H₂   →   2NH₃

We have to solve from the known to the unknown

  • The known specie is the mass of H₂ ;

             find the number of moles of the specie;

    number of moles = \frac{mass}{molar mass}

     Molar mass of H₂ = 2(1) = 2g/mol

   Number of moles  = \frac{0.0008}{2}   = 0.0004mol

  • 3 moles of H₂   will produce 2 moles of NH₃

      0.0004 moles of H₂ will produce \frac{0.0004 x 2}{3}   = 0.00027moles of NH₃

   1 mole of a substance contains 6.02 x 10²³ molecules

     0.00027mole of NH₃ will contain 0.00027 x 6.02 x 10²³

                               = 1.61 x 10²⁰ molecules

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A chemist observes that a large molecule reacts as if it were much smaller. The chemist proposes that the molecule is folded in
nadezda [96]

Answer:

Hypothesis

Explanation:

The following steps are applicable when we wish to prove a specific fact:

  • a hypothesis is made; this is a statement that we provide after some observations and we wish to either prove or deny it;
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In the context of this problem, we're at the first step where we make a hypothesis.

6 0
3 years ago
What is the net charge of the peptide arg-ala-phe-leu at ph 8?
adell [148]
The structure of this oligopeptide is attached:

It consists of arginine - alanine - phenylalanine and leucine

From the picture we can see that N terminus charge is +1
Also Arginine is considered as basic amino acid with charge +1
C terminus charge is -1

At pH = 8, the whose pKa are less than pH will be deprotonated and the net charge will be +1 

So the net charge of this oligopeptide is +1 at pH = 8 

3 0
2 years ago
Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas​
Inessa05 [86]

The relative molecular mass of the gas​ : 64 g/mol

<h3>Further explanation</h3>

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas​

Solution

Graham's Law

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas​

Input the value :

\tt \dfrac{4r_2}{r_2}=\sqrt{\dfrac{M_2}{4} }\\\\16=\dfrac{M_2}{4}\\\\M_2=64~g/mol

7 0
2 years ago
What element is most reactive to gas
sesenic [268]
The element that is most reactive to gas is Hydrogen
4 0
2 years ago
Read 2 more answers
slader An experiment is carried out where 13.9 g of solid NaOH is dissolved in 250.0 g of water in a coffee-cup calorimeter. Dis
kvv77 [185]

Answer:

The mass of the surrounding is M_t = 263.9 \ g

Explanation:

From the question we are told that

      The mass of  NaOH is  m = 13.9 \ g

      The mass of water is m_w = 250.0g

      The chemical equation for the dissociation process is

       NaOH _{(s) } ---> Na^{+}_{(aq)} + OH^{-} _{(aq)}

       The specific heat capacity of the mixture is c_p = 4.18 J g^{-1} C^{-1}

       

The combined mass of the solution is

         M_t = 13 + 250

         M_t = 263.9 \ g

The mass of the surround here is the mass of the coffee-cup calorimeter and this contain the mixture ( water and the NaOH ) so the mass of the surrounding is  

  M_t = 263.9 \ g

       

3 0
3 years ago
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