What is the name of the following Arrhenius acid, H3PO3?

A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO

Akimi4 [234]

Answer: The empirical formula for the given compound is $CH_2$

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of $CO_2=22.0g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, $\frac{12}{44}\times 22.0=6g$ of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = $\frac{0.5}{0.5}=1$

For Hydrogen = $\frac{1.0}{0.5}=2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is $C_{1}H_{2}=CH_2$

4 0

3 years ago

How many half-lives would something have gone through if you had 75% daughter product and 25% parent?

levacccp [35]

Answer:

Two Half-lives

Explanation:

Let number of Parent nuclei Initially present be X,

Then, finally $\frac{X}{4}$ Parent nuclei Will remain with $\frac{3X}{4}$ daughter nuclei.

In one half- life , parent nuclei becomes half of initial.

So, starting with X parent nuclei,

After one half-life, it will degrade to $\frac{X}{2}$ .

After another half life , Parent nuclei will become half of $\frac{X}{2}$

Which is equal to $\frac{X}{4}$ .

So, Parent nuclei have to go through Two half-lives.

6 0

3 years ago

Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will

stiks02 [169]

The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.

The solubility of a substance in water is in accordance with the solubility rules. It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.

Now, we will consider each reaction individually to decode whether or not a precipitate is possible.

In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g) + NaBr(aq) + H2O(l), a precipitate is not formed here.

Learn more: brainly.com/question/11969651

6 0

3 years ago

Please help me with this honestly I'm clueless It's 7th science work......please help

olganol [36]

Hiii
3. describe the physical characters that can be observed: phenotype

6. a specific characteristic of an organism: trait

7. a section of DNA that provides instructions for specific traits: genes

8. allele expressed in the phenotype even if only one copy is present in the genotype: dominant

hope this helped :)

6 0

3 years ago

Read 2 more answers

What is the redox equation for sulphuric acid and magnesium ribbon

Wewaii [24]

Sulfuric acid: $H_2SO_4_{(aq)}$
Magnesium ribbon: $Mg_(s)$
$Mg_{(s)}+H_2SO_4_{(aq)} \rightarrow MgSO_4_{(aq)}+H_2_{(g)}$

8 0

3 years ago