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SpyIntel [72]
3 years ago
14

Answer this for 15 points and Brainliest

Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

y=3x+18

Step-by-step explanation:

Since slope-intercept form is y=mx+b, we first need to find the slope.

m=y2-y1/x2-x1

m=0-(-9)/-6-(-9)

m=9/3=3

Next we need to find b, or the y-intercept

to do that we plug in numbers to what we already have.

y=3x+b

0=-18+b

b=18

Now we put it all together.

<h3>y=3x+18</h3>

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What is the equation of the line that is parallel to the y-axis, containing the ordered pair (1, -3)?
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Parallel to y a-zoos mess horizontal so slope is 0 therefore y=-3
8 0
3 years ago
The longest spin of a basketball on one finger is 255 minutes.about how many hours is that
lidiya [134]

The longest spin of a basketball on one finger is 255 minutes or 4.25 hours.

Step-by-step explanation:

the longest spin of a basketball on one finger is 255 minutes.

We need to find how many hours is that.

So, we need to convert 255 minutes into hours.

We know that,

60 minutes = 1 hour

Using Unitary method:

60 minutes = 1 hour

1 minute = 1/60 hour

255 minutes = 1/60 * 255 hour

255 minutes = 255/60 hour = 4.25 hour

255 minutes is 4.25 hour.

So, The longest spin of a basketball on one finger is 255 minutes or 4.25 hours.

Keywords: Convert Minutes to Hour

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4 0
3 years ago
A bank is trying to determine which model of safe to install. The bank manager believes that each model is equally resistant to
alexandr402 [8]

Answer:

So on this case the 95% confidence interval would be given by (-1.152;5.152).

-1.152 < \mu_{safe1}-\mu_{safe2}  

Should we conclude that the average time it takes experts to crack the safes does not differ by model at the 5% significance level?

A) Yes, the 95% confidence interval for ?D contains 0.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution

Let put some notation  

x=value for Safe 1 , y = value for Safe 2

x: 103, 90, 64, 120, 104, 92, 145, 106, 76

y: 101, 94, 58, 112, 103, 90, 140, 110, 74

The first step is calculate the difference d_i=x_i-y_i and we obtain this:

d: 2, -4, 6, 8, 1, 2, 5, -4, 2

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{18}{9}=2

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =4.093

The next step is calculate the degrees of freedom given by:

df=n-1=9-1=8

Now we need to calculate the critical value on the t distribution with 8 degrees of freedom. The value of \alpha=1-0.95=0.05 and \alpha/2=0.025, so we need a quantile that accumulates on each tail of the t distribution 0.025 of the area.

We can use the following excel code to find it:"=T.INV(0.025;8)" or "=T.INV(1-0.025;8)". And we got t_{\alpha/2}=\pm 2.31

The confidence interval for the mean is given by the following formula:  

\bar d \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

Now we have everything in order to replace into formula (1):  

2-2.31\frac{4.093}{\sqrt{9}}=-1.152  

2+2.31\frac{4.093}{\sqrt{9}}=5.152  

So on this case the 95% confidence interval would be given by (-1.152;5.152).

-1.152 < \mu_{safe1}-\mu_{safe2}  

Should we conclude that the average time it takes experts to crack the safes does not differ by model at the 5% significance level?

A) Yes, the 95% confidence interval for D contains 0.

5 0
3 years ago
A team averaging 110 points is likely to do very well during the regular season. The coach of your team has hypothesized that yo
aev [14]

Answer:

1. M=108

2. μ=110

3. In the explanation.

4. Test statistic t = -1.05

5. P-value = 0.1597

Step-by-step explanation:

The question is incomplete: to solve this problem, we need the sample information: size, mean and standard deviation.

We will assume a sample size of 10 matches, a sample mean of 108 points and a sample standard deviation of 6 points.

1. The mean points is the sample points and has a value of 108 points.

2. The null hypothesis is H0: μ=110, meaning that the mean score is not significantly less from 110 points.

3. This is a hypothesis test for the population mean.

The claim is that the mean score is significantly less than 110.

Then, the null and alternative hypothesis are:

H_0: \mu=110\\\\H_a:\mu< 110

The significance level is 0.05.

The sample has a size n=10.

The sample mean is M=108.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6}{\sqrt{10}}=1.9

4. Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{108-110}{1.9}=\dfrac{-2}{1.9}=-1.05

The degrees of freedom for this sample size are:

df=n-1=10-1=9

5. This test is a left-tailed test, with 9 degrees of freedom and t=-1.05, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.1597) is bigger than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean score is significantly less than 110.

7 0
3 years ago
How do i find the pythagorean theorem of this
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Look it up on safari
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