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Vikentia [17]
3 years ago
10

Solve for w. −(1/4w 8) 8=3 w=52w=52 w=134w=134 w=−34w=−34 w=−12

Mathematics
1 answer:
prohojiy [21]3 years ago
8 0
-(1/4 w + 8) + 8 = 3
-1/4 w - 8 = 3 - 8 = -5
1/4w = -8 + 5 = -3
w = 4 x -3 = -12
w = -12
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3 0
3 years ago
The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of a bridge is 1270 ft long and
deff fn [24]

Answer:

Step-by-step explanation:

Given

span of bridge L=1270\ ft

height of span h=157\ ft

Equation of Parabola

y=0.00039x^2

|x| i.e.

-635

\frac{dy}{dx}=2\times 0.00039

length of Arc=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}

=\int_{-635}^{635}\sqrt{1+(\frac{dy}{dx})^2}

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=2\times \int_{0}^{635}\sqrt{1+(0.00078x)^2}

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4 0
3 years ago
How is adding 6+3 like adding 60+30​
storchak [24]

Answer:

because your just adding a zero at the end.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Anya makes a scale drawing of a bug. The scale of the drawing’s length to the actual bug’s length is 2 inches: 1/8 inch. The act
ioda
<h2>Hello!</h2>

The answer is: The Anya's drawing is 6 inches long.

Have a nice day!

<h2>Why?</h2>

To solve this problem, we need to consider the drawing's length with respect to the actual bug's size, so, the scale factor is:

2in:\frac{1}{8}in\\\\2x(in):\frac{3}{4}in

So, how long is Anya's drawing of the bug?

We can find it, using the following equation:

(2x)in=\frac{2in*\frac{3}{4}in}{\frac{1}{8}in}=\frac{\frac{6}{4}in}{\frac{1}{8}in}=\frac{\frac{3}{2}in }{\frac{1}{8}in}\\\\(2x)in=\frac{\frac{3}{2}in }{\frac{1}{8}in }=\frac{3}{2}in*\frac{8}{1}in=12in^{2}\\\\(2x)in=12in^{2} \\\\x=\frac{12in^{2} }{2in}=6in

Hence, the Anya's drawing is 6 inches long.

Have a nice day!

7 0
3 years ago
Does the system have a no solution or infinitely many solutions<br> Y=2/3x+2-2x+3y=6
oee [108]

Answer:

answer for y=2/3x+2: y=2/3x+2

answer for -2x+3y=6: x=3/2y-3

pls give brainliest

8 0
2 years ago
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