X=0,2,3/8
That is what x equal i don’t know the question but I hope this help
        
             
        
        
        
Answer:b
Step-by-step explanation:
 
        
             
        
        
        
The perpendicular bisector theorem gives the statements that ensures 
that  and
 and  are perpendicular.
 are perpendicular.
The two statements if true that guarantee   is perpendicular to line
 is perpendicular to line  are;
 are;
Reasons:
The given diagram is the construction of the line  perpendicular to line
 perpendicular to line  .
.
Required: 
The two statements that guarantee that   is perpendicular to line
 is perpendicular to line  .
.
Solution:
From the point <em>C</em> arcs <em>E</em> and <em>D</em> are drawn to cross line  , therefore;
, therefore;
 arcs drawn from the same radius.
 arcs drawn from the same radius.
 is perpendicular to line
 is perpendicular to line  , given.
, given.
Therefore;
 by perpendicular bisector theorem.
  by perpendicular bisector theorem.
Learn more about the perpendicular bisector theorem here:
brainly.com/question/11357763
 
        
             
        
        
        
Answer:
   13 ft/s
Step-by-step explanation:
t seconds after the boy passes under the balloon the distance between them is ...
   d = √((15t)² +(45+5t)²) = √(250t² +450t +2025)
The rate of change of d with respect to t is ...
   dd/dt = (500t +450)/(2√(250t² +450t +2025)) = (50t +45)/√(10t² +18t +81)
At t=3, this derivative evaluates to ...
   dd/dt = (50·3 +45)/√(90+54+81) = 195/15 = 13
The distance between the boy and the balloon is increasing at the rate of 13 ft per second.
_____
The boy is moving horizontally at 15 ft/s, so his position relative to the spot under the balloon is 15t feet after t seconds.
The balloon starts at 45 feet above the boy and is moving upward at 5 ft/s, so its vertical distance from the spot under the balloon is 45+5t feet after t seconds.
The straight-line distance between the boy and the balloon is found as the hypotenuse of a right triangle with legs 15t and (45+5t). Using the Pythagorean theorem, that distance is ...
   d = √((15t)² + (45+5t)²)
 
        
             
        
        
        
3.25 is rounded to the nearest thousandth